>我正在努力拉取正确的值
我正在尝试获得以下内容
然后，包>项遍历 ID
{"id":1,"title":"Barnsley","slug":"barnsley","packages":[{"id":1,"title":"Group PACKAGE 1","items"
{"id":9,"title":"Guiness","band_a":null,"band_b":null,"band_c":null,"band_d":null,"band_e":null,"band_f":null,"band_g":null,"band_h":null,"band_i":null,"band_j":null,"variations":null},
{"id":10,"title":"John Smith","band_a":null,"band_b":null,"band_c":null,"band_d":null,"band_e":null,"band_f":null,"band_g":null,"band_h":null,"band_i":null,"band_j":null,"variations":null},
{"id":22,"title":"Chicken Cheese and Bacon Melt","band_a":4.5,"band_b":4.75,"band_c":5.0,"band_d":5.25,"band_e":null,"band_f":null,"band_g":null,"band_h":null,"band_i":null,"band_j":null,"variations":null}],"additional_items":null,"event_types":null}]}
您的 JSON 无效。您缺少声明 items 数组的两个字符:[。修复 JSON 后（jsonlint.com 检查），您可以像这样迭代项目 ID：
$obj = json_decode($str);
foreach($obj->packages[0]->items as $item)
{
echo $item->id;
}
如果可能有多个包，您也可以迭代它们：
foreach($obj->packages as $package)
{
foreach($package->items as $item)
{
echo $item->id;
}
}