听听防火墙符号的句柄方法

我正在Symfony2（.0.x）中开发一个项目，我正在构建一个简单的自动登录系统。现在要做到这一点，我想侦听在防火墙中触发 handle（） 方法的事件。唯一的问题是我找不到该怎么做。（我也在使用FOSUserBundle和FOSFacebookbundle的组合）

有人可以帮助我。（或者告诉我我是否做错了）

这是我的服务：

project.user.auto_login_listener:
        class: Project'UserBundle'Listener'AutoLoginListener
        public: false
        abstract: true
        arguments: [@security.context, @security.authentication.manager, '' , '' , @logger, @event.dispatcher]

在此示例中，我删除了事件侦听器，因为它不起作用

<?php
namespace Project'UserBundle'Listener;
use Symfony'Component'EventDispatcher'EventDispatcherInterface; 
use Symfony'Component'HttpKernel'Event'GetResponseEvent; 
use Symfony'Component'HttpKernel'Log'LoggerInterface; 
use Symfony'Component'Security'Core'SecurityContextInterface; 
use Symfony'Component'Security'Core'Authentication'AuthenticationManagerInterface; 
use Symfony'Component'Security'Core'Exception'AuthenticationException; 
use Symfony'Component'Security'Http'SecurityEvents; 
use Symfony'Component'Security'Http'Event'InteractiveLoginEvent; 
use Symfony'Component'Security'Http'Firewall'ListenerInterface;
class AutoLoginListener implements ListenerInterface {
    private $authenticationManager;
    private $dispatcher;
    private $logger;
    private $providerKey;
    private $securityContext;
    private $tokenParam;

    public function __construct(SecurityContextInterface $securityContext, AuthenticationManagerInterface $authenticationManager, $providerKey, $tokenParam, LoggerInterface $logger = null, EventDispatcherInterface $dispatcher = null)
    {
        $this->securityContext = $securityContext;
        $this->authenticationManager = $authenticationManager;
        $this->providerKey = $providerKey;
        $this->tokenParam = $tokenParam;
        $this->logger = $logger;
        $this->dispatcher = $dispatcher;
    }
    public function handle(GetResponseEvent $event)
    {
         die("test");
    }  
}
?>

谢谢！