PHP 如何在 foreach 循环中计算相同的单词 - PHP How to count same words in foreach loop

PHP How to count same words in foreach loop

本文关键字：计算单词循环 foreach PHP | 更新日期: 2023-09-27

我的foreach循环中有这个结果：

Tonsilitis
Tonsilitis
Laryngitis
Rhinosinusitis Akut
Rhinosinusitis Akut
Rhinosinusitis Akut
Common Cold
Common Cold
Common Cold
Rhinitis Alergi

这是我的脚本：

foreach ($results as $data) :
   $final = $data->nama_diagnosis . '<br>';
   echo $final;
endforeach;

我的问题是，我如何在循环中或循环外计算相同的单词。我能做到吗？请给我解决方案。因此，我想这样计算它们：

Tonsilitis = 2
Laryngitis = 1
Rhinosinusitis Akut = 3
Common Cold = 3
Rhinitis Alergi = 1

或者，也许我可以过滤相同的单词，这样我只能得到最多的单词，例如鼻窦炎和普通感冒。请帮助我。谢谢

您可以尝试这样的事情，使用循环遍历数组foreach并使用带有 isset 的三元运算符安全地分配和递增每个匹配项：

$count = array();
foreach ($results as $result)
    isset($count[$data]) ? $count[$data]++ : $count[$data] = 1;

例

在foreach循环中，将单词及其计数保存到数组中，然后进行另一个循环并写入数量。

<?php
$results = array(
    array('nama_diagnosis' => 'Tonsilitis'),
    array('nama_diagnosis' => 'Tonsilitis'),
    array('nama_diagnosis' => 'Laryngitis'),
    array('nama_diagnosis' => 'Rhinosinusitis Akut'),
    array('nama_diagnosis' => 'Rhinosinusitis Akut'),
    array('nama_diagnosis' => 'Rhinosinusitis Akut'),
    array('nama_diagnosis' => 'Common Cold'),
    array('nama_diagnosis' => 'Common Cold'),
    array('nama_diagnosis' => 'Common Cold'),
    array('nama_diagnosis' => 'Rhinitis Alergi')
);
$res = array();
foreach ($results as $words) {  // changed $word to $words
    foreach ($words as $word) { // this foreach added
        if (isset($res[$word])) {
            $res[$word] += 1;
        } else {
            $res[$word] = 1;
        }
    } // end of nested foreach which was added
}
foreach ($res as $word => $count) {
    echo $word . ' (' . $count . ')<br>';
}
/*
    output:
    Tonsilitis (2)
    Laryngitis (1)
    Rhinosinusitis Akut (3)
    Common Cold (3)
    Rhinitis Alergi (1)
*/
?>

尝试使用 -

$counts = array();
foreach ($results as $data) :
   $final = $data->nama_diagnosis . '<br>';
   if (array_key_exists($data->nama_diagnosis, $counts)) {
        $counts[$data->nama_diagnosis] += 1;
   } else {
        $count[$data->nama_diagnosis] = 1;
   }
endforeach;
foreach ($counts as $key => $val) { 
    echo $key.' = '.$val;
}

这应该适合您：

<?php
    $results = array("Tonsilitis", "Tonsilitis", "Laryngitis", "Rhinosinusitis Akut", "Rhinosinusitis Akut", "Rhinosinusitis Akut", "Common Cold", "Common Cold", "Common Cold", "Rhinitis Alergi");
    $counter = array();

    foreach ($results as $data):
        if(in_array($data->nama_diagnosis, array_flip($counter)))
            $counter[$data->nama_diagnosis]++;
        else
            $counter[$data->nama_diagnosis] = 1;
    endforeach;
    foreach ($counter as $key => $data)
       echo $key . " = " . $data . "<br />"; 
?>

输出：

Tonsilitis = 2
Laryngitis = 1
Rhinosinusitis Akut = 3
Common Cold = 3
Rhinitis Alergi = 1