如何查找字符串中是否存在 2 或 3 个数字的组合，然后将其拆分为两个变量？
示例：$input = "this and that 12"或$input = "this and that 100"
我想将此字符串分为两个变量：
$text = "this and that",
$number = "12"（或如上例中的"100"）
P.S字符串是用户输入，也可以不包含任何数字，示例$input = "this and that";
没有尝试过，但应该可以工作。
$number = preg_replace( '/[^0-9]/', '', $string );
$text = str_replace($number, "", $string);
另一个
$aStrings = array('This and that 123','This and Not That 12');
foreach($aStrings as $str){
preg_match('/'D+/',$str, $text);
preg_match('/'d+/', $str, $num);
echo "
$text[0]
$num[0]
- - - -
";
}
输出：
This and that
123
- - - -
This and Not That
12
- - - -
示例代码
试试这个
<?php
$string1 = "this and that 12";
$string2 = "this and that 100";
$combine = explode(' ',$string1.' '.$string2);
$vars = '';
$integer ='';
foreach($combine as $key =>$val)
{
if(is_numeric($val))
{
$vars[] = $val;
}
else
{
$integer[] =$val;
}
}
echo "<pre>"; print_r(array_unique($vars));
echo "<pre>"; print_r(array_unique($integer));
?>
这将输出
Array
(
[0] => 12
[1] => 100
)
Array
(
[0] => this
[1] => and
[2] => that
)
你试试这段代码
$string="this and that 12";//this and that 100
preg_match_all('/^([^'d]+)('d+)/', $string, $match);
echo $text = $match[1][0];
echo $num = $match[2][0];