PHP 5.4 调用时间传递引用 - 在这里很容易修复


PHP 5.4 Call-time pass-by-reference - Easy fix here?

我在 Centos 5.9、PHP 5.4 和较旧的 PHP 程序扩展(typo3 CMS)中收到此错误消息。

PHP 致命错误:调用时间按引用传递已在第 279 行的 class.tx_spscoutnetcalendar_pi1.php

中删除

这是模拟的php代码函数:

    // ********* Start XML code *********
    // get XML data from an URL and return it
    function fetchCalendarData($xmlUrl,$timeout) {
            $xmlSource="";
            $url = parse_url($xmlUrl);
            $fp = fsockopen($url['host'], "80", &$errno, &$errstr, $timeout);
            if ($fp) {
                    fputs($fp, "GET ".$url['path']."?".$url['query']." HTTP/1.1'r'nHost: " . $url['host'] . "'r'n'r'n");
                    while(!feof($fp))
                    $xmlSource .= fgets($fp, 128);
            }
                    // strip HTTP header
        if ($pos = strpos($xmlSource,"<?xml")) { // this has to be the first line
            $xmlSource = substr($xmlSource, $pos);
        } else {
            $xmlSource="";
        }
    // I have no idea why, but at the end of the fetched data a '0' breaks the XML syntax and provides an 
    // error message in the parser. So I just cut the last 5 characters of the fetched data
    $xmlSource = substr($xmlSource,0,strlen($xmlSource)-5);
            return $xmlSource;
    }

具体到这一行 279

$fp = fsockopen($url['host'], "80", &$errno, &$errstr, $timeout);

请在这里提供任何帮助,我不是 php 专家。

只需像这样删除前导&

$fp = fsockopen($url['host'], "80", $errno, $errstr, $timeout);

变量仍然通过引用传递,但从 PHP 5.4 开始,您不需要&来指示。