如何使用命令行PHP程序查看jpg图像

有没有办法在命令行PHP中查看jpg图像？

我想在命令行PHP程序中循环浏览照片目录，并使用击键，通过利用php stdin对该照片进行操作，例如将其移动到另一个目录。我无法找到从命令行PHP输出每个图像的方法。

谢谢

这是我到目前为止的代码。如果我能查看jpg，我想我可能没事...

<?php
// View the jpg images one at a time
$files = glob("images/*.jpg");
foreach($files as $jpg){
//    echo "<img src='$jpg'></br>";
  echo "view image somehow" . PHP_EOL;
echo "The jpg variable equals '$jpg'" . PHP_EOL;
// show them a message to enter letter for category
echo "Enter the category, a(family), r(friends), c(coworkers), d(delete), ctrl-letter(two folders)" . PHP_EOL;
// the script will wait here until the user has entered something and hit ENTER
$category = read_stdin();
// This will display the category message including the category they entered.
echo "You chose $category . Next photo" . PHP_EOL;
switch ($category) {
    case "a":
        echo "$category equals family" . PHP_EOL;
        r    ename("$jpg", "images/sorted/family/$jpg");
        break;
    case "r":
        echo "$category equals friends" . PHP_EOL;
        rename("$jpg", "images/sorted/friends/$jpg");
        break;
    case "c":
        echo "$category equals coworkers" . PHP_EOL;
        rename("$jpg", "images/sorted/coworkers/$jpg");
        break;
    default:
       echo "$category is not equal to a,r, or c" . PHP_EOL;
 }
}
// our function to read from the command line
function read_stdin()
{
        $fr=fopen("php://stdin","r");   // open our file pointer to read from stdin
        $input = fgets($fr,128);        // read a maximum of 128 characters
        $input = rtrim($input);         // trim any trailing spaces.
        fclose ($fr);                   // close the file handle
        return $input;                  // return the text entered
}
?>