我正在尝试将 php 变量传递到 java 脚本窗口中。我似乎无法正确语法。
法典:
function confirmation(a) {
var currString = "<? echo $currString ?>";
var answer = confirm("Are you sure you want to delete this item?")
if (answer){
alert("The item has been deleted")
window.location = "list.php?s='. $currString .'&=delete=true&id=" + a;
}
else{
alert("The item has not been deleted")
}
试试这个:
function confirmation(a) {
var currString = "<?php echo $currString ?>";
var answer = confirm("Are you sure you want to delete this item?");
if (answer){
alert("The item has been deleted")
window.location = "list.php?s=" + currString + "&=delete=true&id=" + a;
}
else{
alert("The item has not been deleted");
}
你正在将php变量添加到JS变量 var currString = ";
在window.location
你再次传递PHP变量是错误的,
所以这样做
window.location = "list.php?s=" + currString + "&=delete=true&id=" + a;
语法问题已通过其他答案解决,但您需要处理另一个问题:在 URL 中使用变量时对变量进行 URI 编码:
window.location = "list.php?s="
+ encodeURIComponent(currString)
+ "&=delete=true&id=" + a;
否则,您会遇到变量包含&
等字符的问题。
echo "<script>alert('System info has been Save')</script>";
echo "<script>window.location='customer_detail.php?
customer_id=".$customer_id."'</script>";