我正在使用这个函数（我在这个论坛上找到的）来计算一个范围之间的工作日数：
<?php
//The function returns the no. of business days between two dates and it skips the holidays
function getWorkingDays($startDate,$endDate,$holidays){
// do strtotime calculations just once
$endDate = strtotime($endDate);
$startDate = strtotime($startDate);
//The total number of days between the two dates. We compute the no. of seconds and divide it to 60*60*24
//We add one to inlude both dates in the interval.
$days = ($endDate - $startDate) / 86400 + 1;
$no_full_weeks = floor($days / 7);
$no_remaining_days = fmod($days, 7);
//It will return 1 if it's Monday,.. ,7 for Sunday
$the_first_day_of_week = date("N", $startDate);
$the_last_day_of_week = date("N", $endDate);
//---->The two can be equal in leap years when february has 29 days, the equal sign is added here
//In the first case the whole interval is within a week, in the second case the interval falls in two weeks.
if ($the_first_day_of_week <= $the_last_day_of_week) {
if ($the_first_day_of_week <= 6 && 6 <= $the_last_day_of_week) $no_remaining_days--;
if ($the_first_day_of_week <= 7 && 7 <= $the_last_day_of_week) $no_remaining_days--;
}
else {
// (edit by Tokes to fix an edge case where the start day was a Sunday
// and the end day was NOT a Saturday)
// the day of the week for start is later than the day of the week for end
if ($the_first_day_of_week == 7) {
// if the start date is a Sunday, then we definitely subtract 1 day
$no_remaining_days--;
if ($the_last_day_of_week == 6) {
// if the end date is a Saturday, then we subtract another day
$no_remaining_days--;
}
}
else {
// the start date was a Saturday (or earlier), and the end date was (Mon..Fri)
// so we skip an entire weekend and subtract 2 days
$no_remaining_days -= 2;
}
}
//The no. of business days is: (number of weeks between the two dates) * (5 working days) + the remainder
//---->february in none leap years gave a remainder of 0 but still calculated weekends between first and last day, this is one way to fix it
$workingDays = $no_full_weeks * 5;
if ($no_remaining_days > 0 )
{
$workingDays += $no_remaining_days;
}
//We subtract the holidays
foreach($holidays as $holiday){
$time_stamp=strtotime($holiday);
//If the holiday doesn't fall in weekend
if ($startDate <= $time_stamp && $time_stamp <= $endDate && date("N",$time_stamp) != 6 && date("N",$time_stamp) != 7)
$workingDays--;
}
return $workingDays;
}
//Example:
$holidays=array("2008-12-25","2008-12-26","2009-01-01");
echo getWorkingDays("$startdate","$enddate",$holidays)
?>
现在我想稍微扩展一下这个函数。我想生成如果我从开始日期添加 X 个工作日，它将是哪个日期。例如，假设我有一个保存值 20 的变量
$workingdays = "20";
$startdate是2012-06-01我想让这个函数计算开始日期 + 20 个工作日将是 2012-06-28。这可能吗？
不久
前我使用以下函数做了类似的事情。 这里的关键是跳过周末，您也可以将其扩展到跳过假期。
例：
调用函数 -> addDays(strtotime($startDate), 20, $skipdays,$skipdates = array())
<?php
function addDays($timestamp, $days, $skipdays = array("Saturday", "Sunday"), $skipdates = NULL) {
// $skipdays: array (Monday-Sunday) eg. array("Saturday","Sunday")
// $skipdates: array (YYYY-mm-dd) eg. array("2012-05-02","2015-08-01");
//timestamp is strtotime of ur $startDate
$i = 1;
while ($days >= $i) {
$timestamp = strtotime("+1 day", $timestamp);
if ( (in_array(date("l", $timestamp), $skipdays)) || (in_array(date("Y-m-d", $timestamp), $skipdates)) )
{
$days++;
}
$i++;
}
return $timestamp;
//return date("m/d/Y",$timestamp);
}
?>
[编辑]：刚刚阅读了一篇关于nettuts的精彩文章，希望这对 http://net.tutsplus.com/tutorials/php/dates-and-time-the-oop-way/有所帮助
如果有人感兴趣，我正在使用此功能将 X 个工作日添加到日期。该函数接收时间戳并返回时间戳。可以通过数组指定假期（如果在美国，您可以使用 usBankHolidays() ）。
目前，假设周六和周日不是工作日，但可以轻松更改。
代码：
function addBusinessDays($date, $days, $holidays = array()) {
$output = new DateTime();
$output->setTimestamp($date);
while ($days > 0) {
$weekDay = $output->format('N');
// Skip Saturday and Sunday
if ($weekDay == 6 || $weekDay == 7) {
$output = $output->add(new DateInterval('P1D'));
continue;
}
// Skip holidays
$strDate = $output->format('Y-m-d');
foreach ($holidays as $s) {
if ($s == $strDate) {
$output = $output->add(new DateInterval('P1D'));
continue 2;
}
}
$days--;
$output = $output->add(new DateInterval('P1D'));
}
return $output->getTimestamp();
}
function usBankHolidays($format = 'datesonly') {
$output = array(
array('2015-05-25', 'Memorial Day'),
array('2015-07-03', 'Independence Day'),
array('2015-09-07', 'Labor Day'),
array('2015-10-12', 'Columbus Day'),
array('2015-11-11', 'Veterans Day'),
array('2015-11-26', 'Thanksgiving Day'),
array('2015-12-25', 'Christmas Day'),
array('2016-01-01', 'New Year Day'),
array('2016-01-18', 'Martin Luther King Jr. Day'),
array('2016-02-15', 'Presidents Day (Washingtons Birthday)'),
array('2016-05-30', 'Memorial Day'),
array('2016-07-04', 'Independence Day'),
array('2016-09-05', 'Labor Day'),
array('2016-10-10', 'Columbus Day'),
array('2016-11-11', 'Veterans Day'),
array('2016-11-24', 'Thanksgiving Day'),
array('2016-12-25', 'Christmas Day'),
array('2017-01-02', 'New Year Day'),
array('2017-01-16', 'Martin Luther King Jr. Day'),
array('2017-02-20', 'Presidents Day (Washingtons Birthday)'),
array('2017-05-29', 'Memorial Day'),
array('2017-07-04', 'Independence Day'),
array('2017-09-04', 'Labor Day'),
array('2017-10-09', 'Columbus Day'),
array('2017-11-10', 'Veterans Day'),
array('2017-11-23', 'Thanksgiving Day'),
array('2017-12-25', 'Christmas Day'),
array('2018-01-01', 'New Year Day'),
array('2018-01-15', 'Martin Luther King Jr. Day'),
array('2018-02-19', 'Presidents Day (Washingtons Birthday)'),
array('2018-05-28', 'Memorial Day'),
array('2018-07-04', 'Independence Day'),
array('2018-09-03', 'Labor Day'),
array('2018-10-08', 'Columbus Day'),
array('2018-11-12', 'Veterans Day'),
array('2018-11-22', 'Thanksgiving Day'),
array('2018-12-25', 'Christmas Day'),
array('2019-01-01', 'New Year Day'),
array('2019-01-21', 'Martin Luther King Jr. Day'),
array('2019-02-18', 'Presidents Day (Washingtons Birthday)'),
array('2019-05-27', 'Memorial Day'),
array('2019-07-04', 'Independence Day'),
array('2019-09-02', 'Labor Day'),
array('2019-10-14', 'Columbus Day'),
array('2019-11-11', 'Veterans Day'),
array('2019-11-28', 'Thanksgiving Day'),
array('2019-12-25', 'Christmas Day'),
array('2020-01-01', 'New Year Day'),
array('2020-01-20', 'Martin Luther King Jr. Day'),
array('2020-02-17', 'Presidents Day (Washingtons Birthday)'),
array('2020-05-25', 'Memorial Day'),
array('2020-07-03', 'Independence Day'),
array('2020-09-07', 'Labor Day'),
array('2020-10-12', 'Columbus Day'),
array('2020-11-11', 'Veterans Day'),
array('2020-11-26', 'Thanksgiving Day'),
array('2020-12-25', 'Christmas Day '),
);
if ($format == 'datesonly') {
$temp = array();
foreach ($output as $item) {
$temp[] = $item[0];
}
$output = $temp;
}
return $output;
}
用法：
$deliveryDate = addBusinessDays(time(), 7, usBankHolidays());
从 @this.lau_ 回答重写更简单、更合乎逻辑的算法，具有动态（固定）圣日
public function addBusinessDays($date, $days) {
$output = new DateTime();
$output->setTimestamp($date);
while ($days > 0) {
$output = $output->add(new DateInterval('P1D'));
$weekDay = $output->format('N');
$strDate = $output->format('Y-m-d');
// Skip Saturday and Sunday
if ($weekDay == 6 || $weekDay == 7) {
continue;
}
// Skip holidays
$holidays = $this->_getHolidays();
foreach ($holidays as $holiday_date => $holiday_name) {
if ($holiday_date == $strDate) {
continue 2;
}
}
$days--;
}
return $output->getTimestamp();
}
public function _getHolidays() {
$feste = array(
date("Y") . "-01-01" => "Capodanno",
date("Y") . "-01-06" => "Epifania",
date("Y") . "-04-25" => "Liberazione",
date("Y") . "-05-01" => "Festa Lavoratori",
date("Y") . "-06-02" => "Festa della Repubblica",
date("Y") . "-08-15" => "Ferragosto",
date("Y") . "-11-01" => "Tutti Santi",
date("Y") . "-12-08" => "Immacolata",
date("Y") . "-12-25" => "Natale",
date("Y") . "-12-26" => "St. Stefano"
);
return $feste;
}
调用函数
$deliveryDate = addBusinessDays(time(), 7);
使用this.lau_函数，我可以反转它，减去日期，使用到期日期。希望这对某人有所帮助：
function subBusinessDays( $date, $days, $holidays = array() ) {
$output = new DateTime();
$output->setTimestamp( $date );
while ( $days > 0 ) {
$output = $output->sub( new DateInterval( 'P1D' ) );
// Skip holidays
$strDate = $output->format( 'Y-m-d' );
if ( in_array( $strDate, $holidays ) ) {
// Skip Saturday and Sunday
$output = $output->sub( new DateInterval( 'P1D' ) );
continue;
}
$weekDay = $output->format( 'N' );
if ($weekDay <= 5 ) {
$days --;
}
}
return $output->getTimestamp();
}
我有一个更好的解决方案，函数上只有两个参数。
只需调用函数
addDays($currentdate, $WordkingDatestoadd);
然后，使用以下函数
function addDays($timestamp, $days) {
$workingDays = [1, 2, 3, 4, 5]; # date format = N (1 = Monday, ...)
$holidayDays = ['*-12-25', '*-01-01']; # variable and fixed holidays
$timestamp = new DateTime($timestamp);
$days = $days;
for($i=1 ; $i <= $days; $i++){
$timestamp = $timestamp->modify('+1 day');
if ((!in_array($timestamp->format('N'), $workingDays)) && (!in_array($timestamp->format('*-m-d'), $holidayDays))){
$i--;
}
}
$timestamp = $timestamp->format('Y-m-d');
return $timestamp;
}
在这里，
我动态地使用 HolidayAPI 作为假期列表。HolidayAPI 是免费实现的。我是孟加拉国人，这就是为什么我使用国家代码BD。API 链接 - https://holidayapi.com/v1/holidays?pretty&key=your_key&country=your_country_code&year=2020
// cURL start
$cURLConnection = curl_init();
curl_setopt($cURLConnection, CURLOPT_URL, 'your api');
curl_setopt($cURLConnection, CURLOPT_RETURNTRANSFER, true);
$phoneList = curl_exec($cURLConnection);
curl_close($cURLConnection);
$dateResponse = json_decode($phoneList);
// cURL end
$holidays = array(); //declear holidays array`enter code here`
for ($i=0;$i<count($dateResponse->holidays);$i++){
$holidays[] = $dateResponse->holidays[$i]->date; //inserting holidays in array from api
}
$startDate = "2020-02-26"; //insert value thats you prefer
$timestamp = strtotime($startDate); // convert date to time
$weekends = array("Friday", "Saturday");
$days = 0; //initialization days counter
while (1){ //
$timestamp = strtotime("+1 day", $timestamp); //day increment
if ( (in_array(date("l", $timestamp), $weekends)) || (in_array(date("Y-m-d", $timestamp), $holidays)) ) //checking weekends and holidays
{
continue;
}else{
$days++;``
if($days >= 5){ //interval - What will be the working days after 5 days
echo date("Y-m-d", $timestamp); // print expected output
break;
}
}
}
输入： 2020-02-26产量： 2020-03-05