将行和动态文本框插入到 mysql 中 - Inserting rows and dynamic textboxes into a mysql

请我需要您的帮助，从表格和动态文本字段中抓取行，然后将其插入到另一个表格中。我正在尝试从下表中获取一些特定state_id，与同一页面上显示<input type='text' name='constituency[]' />文本框中的数据相结合，然后插入到表格中

                    +---------+--------------------------+
                    |state_id |  state   |   senatorial  |  
                    |--- -----|----------|---------------|
                    |    1    |  utah    |    A-North    | 
                    |    2    |  utah    |    B-South    |  
                    +---------+----------+---------------+

我用来获取信息的 HTML。选区是一个动态文本字段，并且多次出现，因此需要将其放在数组中

                    <input type='hidden' name="state_id[]"   value="<?php echo $row['state_id'];?>" />
                    <input type='text'   name='constituency[]' />

我用来插入到表中的查询

                    <?php
$constituencys = $_POST['constituency']      ; 
        $state_id = $_POST['state_id']; 

         if(isses($_POST['constituency']))
   {
$constituencys = $_POST['constituency']      ;   
                      foreach($constituencys as          $constituency) {  
     $state_id[$i]= $state_id[$i];
                      $query = mysql_query(" 
         INSERT INTO `constituency` (
                    `constituency_id`,
                    `state_id`,
                    `constituency_name`
                    ) VALUES (
                    NULL,
                    '".$state_id[$i]."',
                    '".$constituency."'
                    "); 
                       }

                    if(mysql_affected_rows()>0){
                    echo "Inserted Successfully";
                    }else{
                    echo "No Row Inserted";
                    echo mysql_error() ;
                    echo"<br>Error:".mysql_error();
                   echo"<br>Query:".$query; 
      } } ?>

我插入的表看起来像这样

                    +----------------+-------------+----------------------+
                    |constituency_id |  state_id   |   constituency_name  |  
                    +----------------+-----   -----+----------------------+

当我运行代码"未插入行"时显示在屏幕上

请帮助我。我非常感谢，谢谢。

显示错误

    Error: You have an error in your mysql syntax; check the manual that corresponds to your mysql server for the right syntax to use near " at line 2
Query:

<?php
$constituencys = $_POST['constituency']; 
$state_id = $_POST['state_id']; 
$i = 0;
while($i<count($constituencys)){
    $constituencys[$i]= $constituencys[$i];
    $state_id[$i]= $state_id[$i];
    $query = "INSERT INTO `constituency` ( 
        `constituency_id`, `state_id`, `constituency_name`
        ) VALUES (
        NULL,
        '".$state_id[$i]."',
        '".$constituencys[$i]."'
        "; 
    mysql_query($query);          
    $i++;  
}
if(mysql_affected_rows()>0){
    echo "Inserted Successfully";
} else {
    echo "No Row Inserted";
    echo "<br><br>Error: " . mysql_error();
    echo "<br><br>Query: " . $query;
} 
?>

首先尝试此代码，使用结果更新您的帖子。

更新

看起来您可能有"脏"输入。确保在插入之前使用 mysql 对其进行清理，方法是使用 mysql_real_escape_string。请尝试以下代码。

<?php
$constituencys = $_POST['constituency']; 
$state_id = $_POST['state_id']; 
$i = 0;
while($i<count($constituencys)){
    $constit = mysql_real_escape_string($constituencys[$i]);
    $state = mysql_real_escape_string($state_id[$i]);
    $query = "INSERT INTO `constituency` ( 
        `constituency_id`, `state_id`, `constituency_name`
        ) VALUES (
        NULL,
        '$state',
        '$constit')
        "; 
    mysql_query($query);          
    $i++;  
}
if(mysql_affected_rows()>0){
    echo "Inserted Successfully";
} else {
    echo "No Row Inserted";
    echo "<br><br>Error: " . mysql_error();
    echo "<br><br>Query: " . $query;
} 
?>

注意：在查询结束时，您缺少一个右括号。它已添加到第二个示例中。在继续测试之前，请确保它在那里。

<?php
$constituencys = $_POST['constituency']; 
$state_id = $_POST['state_id']; 
$query = "INSERT INTO `constituency` (`constituency_id`, `state_id`, `constituency_name`) VALUES";
for($i=0; $i<count($constituencys); $i++){
    $constit = mysql_real_escape_string($constituencys[$i]);
    $state = mysql_real_escape_string($state_id[$i]);
    $query .= "(NULL, '$state', '$constit'), "; 
}
$query = substr(trim($query), 0, -1); //trims then removes trailing comma
mysql_query($query);          
if(mysql_affected_rows()>0){
    echo "Inserted Successfully";
} else {
    echo "No Row Inserted";
    echo "<br><br>Error: " . mysql_error();
    echo "<br><br>Query: " . $query;
} 
?>

假设您的 HTML 输入已正确设置为数组，这应该可以工作。它还可以整理您的代码并有助于解决不必要的延迟。每一毫秒都很重要。:)如果这不起作用，请发布返回的错误并再次查询。