正则表达式用于获取键值,包括空格


Regex to grab key-value including the empty space

我有一个问题,无法从我的正则表达式中获取具有空格的值。任何人都可以帮助我使用键值机制向正确的正则表达式提供。请注意,键值位置可能会更改,并且不会固定。

正则表达式

's*(['w'd_]*)=(.*?)'s+

输入

spt=38271 deviceExternalId=SUKUK node 1 dst=99.111.185.141 app=HTTPS rt=Jan 23 2013 15:30:45 deviceFacility=Packet filter msg=Connection was reset by server destinationTranslatedPort=443 

我的结果

Match 1: spt=38271 
    Subgroups:
    1: spt
    2: 38271
Match 2: deviceExternalId=SUKUK 
    Subgroups:
    1: deviceExternalId
    2: SUKUK
Match 3:  dst=99.111.185.141 
    Subgroups:
    1: dst
    2: 99.111.185.141
Match 4: app=HTTPS 
    Subgroups:
    1: app
    2: HTTPS
Match 5: rt=Jan 
    Subgroups:
    1: rt
    2: Jan          **==>Should grab [Jan 23 2013 15:30:45]**
Match 6:  deviceFacility=Packet 
    Subgroups:
    1: deviceFacility
    2: Packet       **==>Should grab [Packet filter]**
Match 7:  msg=Connection 
    Subgroups:
    1: msg
    2: Connection   **==>Should grab [Connection was reset by server]**
Match 8:  destinationTranslatedPort=443 
    Subgroups:
    1: destinationTranslatedPort
    2: 443

试试这个:

(['w'd_]+)=(.*?)(?='s+['w'd_]+=|$)
print "$1'n$2";

更简单:'s*(['w'd_]*)=([^=]+)'s+