我已经简化了这个问题。但是，如果选中按钮组合，我需要做的就是显示不同的结果。目前，如果检查大米和茶，则没有结果。
<?PHP
if (isset($_POST['Submit1'])) {
$selected_radio = $_POST['food']."|".$_POST['drink'];
if ($selected_radio == 'rice' && 'tea') {
print '<h1>Rice and tea</h1>';
}
else if ($selected_radio == 'beans' && 'coffee') {
print '<h1>Beans and coffee</h1>';
}
}
?>
<form name ="form1" method ="POST" action =" ">
<p><input type = 'Radio' Name ='food' value= 'rice'>Rice</p>
<p><input type = 'Radio' Name ='food' value= 'beans'>Beans</p>
<p><input type = 'Radio' Name ='drink' value= 'tea'>Tea</p>
<p><input type = 'Radio' Name ='drink' value= 'coffee'>Coffee</p>
<input type = "Submit" Name = "Submit1" value = "Select">
</form>
（很抱歉之前问过类似的问题）
如果条件更新
if (isset($_POST['Submit1'])) {
$selected_radio = $_POST['food']."|".$_POST['drink'];
if ($selected_radio == 'rice|tea') {
print '<h1>Rice and tea</h1>';
}
else if ($selected_radio == 'beans|coffee') {
print '<h1>Beans and coffee</h1>';
}
}
更改 if 的条件：
if (strpos($selected_radio, 'rice') !== FALSE && strpos($selected_radio, 'tea') !== FALSE) {
print '<h1>Rice and tea</h1>';
}
else if (strpos($selected_radio, 'beans') !== FALSE && strpos($selected_radio, 'coffee') !== FALSE) {
print '<h1>Beans and coffee</h1>';
}
（这只是一个建议，我没有测试它;)）
使用以下代码：
$selected_radio_list = [
'rice|tea' => 'foo',
'beans|coffee' =>'bar'
];
$post = $_POST['food']. "|" .$_POST['drink'];
if(in_array($post, $selected_radio_list )){
echo $selected_radio_list[$post];
}