MySQL按日期时间选择一列中的所有唯一行和另一列中的所有最大行


mysql select all unique rows in one column and all max rows in another column by datetime

我需要的是获取每个table_id的最新(按date_time)unique player_id

桌子:

buyin_id   player_id   table_id       date_time
---------|-----------|----------|--------------------|
    1    |    10     |    21    | 2015-01-26 00:00:01
    2    |    11     |    21    | 2015-01-26 00:00:02
    3    |    12     |    21    | 2015-01-26 00:00:03
    4    |    10     |    21    | 2015-01-26 00:00:04
    5    |    11     |    21    | 2015-01-26 00:00:05
    6    |    12     |    22    | 2015-01-26 00:00:06
    7    |    13     |    22    | 2015-01-26 00:00:07
    8    |    13     |    22    | 2015-01-26 00:00:08

期望的结果:

buyin_id   player_id   table_id       date_time
---------|-----------|----------|--------------------|
    3    |    12     |    21    | 2015-01-26 00:00:03
    4    |    10     |    21    | 2015-01-26 00:00:04
    5    |    11     |    21    | 2015-01-26 00:00:05
    6    |    12     |    22    | 2015-01-26 00:00:06
    8    |    13     |    22    | 2015-01-26 00:00:08

我尝试了这样的事情,它只返回 1 行,而不是每table_id 1 行

SELECT pb.buyin_id, pb.player_id, pb.buyin, pb.cashout, pb.cashout_error, pb.date_time
FROM poker_buyin AS pb
INNER JOIN (SELECT player_id, MAX(date_time) AS MaxDateTime
FROM poker_buyin GROUP BY player_id) groupedpb 
ON pb.player_id = groupedpb.player_id 
AND pb.date_time = groupedpb.MaxDateTime
WHERE pb.player_id = '$player_id'";

您提到的查询查找每个玩家 ID 的最新记录。然后你过滤它,只找到一个玩家,所以你得到一行。

如果要查找每个玩家和牌桌的最新记录,则内部查询需要如下所示:

            SELECT  MAX(buyin_id) buyin_id
              FROM  poker_buyin
             GROUP  BY player_id, table_id

这将从您的表中获取代表最新玩家/桌组合的行 ID。

然后,您可以使用它从表中提取记录,如下所示(http://sqlfiddle.com/#!2/be68b7/2/0)

SELECT whatever_columns
  FROM poker_buyin
 WHERE buyin_id IN
       (
            SELECT  MAX(buyin_id) buyin_id
              FROM  poker_buyin
             GROUP  BY player_id, table_id
       )
 WHERE player_id = '$player_id'
 ORDER BY player_id, table_id

此查询中有一个小技巧:buyin_id值不断上升,因此这是为每个组合选择最新时间记录的好方法。

如果您不需要在结果列中buyin_id很简单:

SELECT DISTINCT player_id, table_id, max(date_time) as dt 
FROM `poker_buyin ` 
GROUP BY player_id, table_id