我有这样的字符串数据列表:
Category(1,2,"some text");
post(111,233,"post");
post(111,233,"post");
post(111,233,"post");
Category(1,2,"some text");
post(111,233,"post");
post(111,233,"post");
post(111,233,"post");
post(111,233,"post");
post(111,233,"post");
我需要以相同的顺序将其转换为数组,例如:
Array
(
[0] => Array
(
['category'] => Category(1,2,"some text")
['posts'] => Array
(
[0] => post(111,233,"post")
[1] => post(111,233,"post")
[2] => post(111,233,"post")
)
)
[2] => Array
(
['category'] => Category(1,2,"some text")
['posts'] => Array
(
[0] => post(111,233,"post")
[1] => post(111,233,"post")
[2] => post(111,233,"post")
[3] => post(111,233,"post")
[4] => post(111,233,"post")
)
)
)
我可以单独获取类别数组并单独获取帖子数组,但是如何以相同的顺序将它们放在一个数组中..
preg_match_all("/(category)'(+(.*?)')/",$string,$cats , PREG_SET_ORDER);
preg_match_all("/(post)'(+(.*?)')/",$string,$posts , PREG_SET_ORDER);
print_r($cats);
print_r($posts);
谢谢
您可以标记字符串,然后逐个解析每个项目,如下所示:
$result = array();
$token_list = explode(";'n",$string);
$category_counter = -1;//index trick for the first occorrence of Category
foreach($token_list as $token){
if(substr($token,0,8) == "Category"){
$category_counter++;
$result[$category_counter]["category"] = $token;
}else{
$result[$category_counter]["posts"][] = $token;
}
}