我正在尝试从数组中删除除 DTSTART 和 DTEND 之外的所有内容
所以我正在尝试转换这个:
Array
(
[0] => Array
(
[DTEND] => 20130417
[DTSTART] => 20130403
[UID] => cerog90g7-fcqls51z0wteew@airbnb.com
[DESCRIPTION] => CHECKIN: 04/08/2012'nCHECKOUT: 04/17/2012'nNIGHTS: 14'nPHO
[NE] => +1 504 914 0591'nEMAIL: testhere@email.com'nPROPERTY: Breathtaking views over the lake'n
[SUMMARY] => Name here (ED5ASC)
[LOCATION] => Breathtaking views over the lake
)
[1] => Array
(
[DTEND] => 20131231
[DTSTART] => 20131226
[UID] => rtyrtyg90g7--t520wkwqv2i8@airbnb.com
[DESCRIPTION] => CHECKIN: 12/26/2013'nCHECKOUT: 12/31/2013'nNIGHTS: 5'nPHON
[E] => +44 7843 387767'nEMAIL: floraking@hotmail.com'nPROPERTY: Breathtaking views over the lake'n
[SUMMARY] => Name here (JrtyKW9)
[LOCATION] => Breathtaking views over the lake
)
[2] => Array
(
[DTEND] => 20121123
[DTSTART] => 20121117
[UID] => ntry5rxts23--qe9rtyrywi0@airbnb.com
[SUMMARY] => Not available
)
)
看起来像这样:
Array
(
[0] => Array
(
[DTEND] => 20130417
[DTSTART] => 20130403
)
[1] => Array
(
[DTEND] => 20131231
[DTSTART] => 20131226
)
)
[2] => Array
(
[DTEND] => 20121123
[DTSTART] => 20121117
)
)
我已经搜索了大量选项,但我需要能够只选择这两个元素并丢弃其余元素,我将它与具有不同值的不同数组一起使用,因此不能只指定要删除的元素,因为它们会有所不同。
$newArray = array();
foreach ($array as $k => $v) {
$newArray[$k]['DTEND'] = $v['DTEND'];
$newArray[$k]['DTSTART'] = $v['DTSTART'];
}
编辑:另一种选择,因为您提到尝试使用数组迭代器函数之一来执行此操作。
array_walk($array, function(&$v){
$v = array('DTEND' => $v['DTEND'],'DTSTART' => $v['DTSTART']);
});
编辑2:因为我没有生命...另一种选择...
array_walk($array, function(&$v){
$v = array_intersect_key($v, array_flip(preg_grep('~^DT(END|START)$~', array_keys($v))));
});
我不知道哪一个最快/最有效,但我的钱可能在第二个。
您可以从每个元素中删除键/值哈希
unset($array[0]['UID']);
unset($array[0]['DESCRIPTION');
//...
unset($array[999]['UID']);
unset($array[999]['DESCRIPTION');
在这种情况下,制作一个新数组会更快,就像蜡笔暴力建议的那样。