刚刚清除了我的缓存和cookie,现在我有以下错误


Just cleared my cache and cookies now I have the following errors

再次感谢那些建议和帮助我的代码的人。 不幸的是,在我清除缓存和 cookie 之前,一切正常。 有 3 个以前不存在的错误。 以下错误是:

注意:未定义的变量:用户名在 C:''xampp''htdocs''Assignment_3''login.php 第 29 行注意:未定义的变量:用户名在 C:''xampp''htdocs''Assignment_3''login.php 在第 34 行警告:session_start():会话 ID 太长或包含非法字符,有效字符为 a-z、A-Z、0-9 和 '-',在第 37 行的 C:''xampp''htdocs''Assignment_3''login.php

前 2 个是一个惊喜,因为我发誓我解决了这个问题。 另一方面,最后一个错误对我来说是全新的。 以前没有遇到过这个问题。 我将发布我的登录名.php以便更好地参考。 同样,任何帮助将不胜感激!

登录.php

<?php

//GOT USER ID COOKIE? IF SO GET IT
if(isset($_COOKIE["userid"])) {
    $username = $_COOKIE["userid"];
}
//NO USER ID? GET THE COOKIE
else {
    //SET COOKIE, EXPIRE IN 600 SECONDS
    setcookie("userid", $username, time()+600 );
}
//SESSION ID IS OUR UNIQUE COOKIE
session_id($username);
//STARTING SESSION
session_start();
$_SESSION['logged_in'] = true;
//TOTAL AMOUNT OF TIME USER WAS LOGGED IN
$_SESSION['time_logged_in'] = time();

//THIS PAGE WILL PROMPT THE USER TO LOGIN WITH AN ALREADY REGISTERED USERNAME AND PASSWORD IN THE DATABASE
//IT WILL CHECK IN THE DATABASE TO SEE IF THE USERNAME AND PASSWORD ARE IN THE SAME ARRAY
//IF NOT THEN IT WILL SAY LOGIN FAILE.
//INCLUDE FUNCTIONS
include "functions.inc";
//IF THE ERRORS ARE SET TO FALSE, ECHO THE ERROR MESSAGES
if (!isset($errors)) $errors = array();
//INITIATE VARIABLE TO ACCESS THE USER DATABASE
$userfile = "user_data.dat";
$currentuser = "curren_user.dat";
//IF THE LOGIN BUTTON WAS PRESSED THEN VALIDATE THAT THE USER AND PASSWORD ARE IN THE SAME ARRAY
//IF NOT, THEN ECHO ERROR MESSAGE.
//IF THEY MATCH, THEN GO TO THE SUCCESSFUL LOGIN PAGE.
if (array_key_exists("login_btn", $_POST))
{
    $logins = arrayfile_to_array($userfile);
    $userlogin = $_POST['user'];

    if (validate_login(strtolower($userlogin['name']), $userlogin['pass'], $logins))
    {
        $errors['login'] = "Invalid Login";
        //break; taken out 11/9/2013
    }
    if (count($errors) == null)
    {
        //QUESTIONABLE VARIABLE
        $_SESSION['username'] = $userlogin['name'];
        header("Location: success_login.php");
    }
}

//IF THE USER HITS THE REGISTER NEW USER BUTTON,
//THEN TAKES THEM TO THE REGISTER NEW USER PAGE.
if (array_key_exists("register_btn", $_POST))
{
    header("Location: registration_page.php");
}
//PRINTING THE LOGIN USER INPUT FORMS.
//INCLUDES USERNAME AND PASSWORD.
//IF USERNAME AND PASSWORD DO NOT MATCH,
//HAS STUCKY FORM AND WILL ECHO ERROR MESSAGE AT TOP.
?>

<center>
<H1>Log In</H1>
<?php if (isset($errors['login'])) echo " <font color='red'>{$errors['login']}</font>"; ?>
<form method="POST" action="login.php"> 
    <table>
    <!--Text input for login-->
    <tr><td>Username:</td>
    <td><input type = 'TEXT'
           name = 'user[name]'
           value = '<?php  if(isset($_POST["user"])) {$tmp = $_POST["user"]; echo $tmp["name"]; } ?>'></td></tr>
    <br>
    <tr><td>Password:</td>
    <!--Password input for new password-->
    <td><input type = 'PASSWORD'
           name = 'user[pass]'
           value = '<?php  if(isset($_POST["user"])) {$tmp = $_POST["user"]; echo $tmp["pass"]; } ?>'></td></tr>
    <br>
    <tr></tr>
    <br>
    <!--Button to go back to form to fill again after errors are realized-->
    <tr><td><input type = 'SUBMIT'
         name = 'login_btn'
         value = 'Login'></td>
    <br>
    <!--Button to go back to form to fill again after errors are realized-->
    <td><input type = 'SUBMIT'
         name = 'register_btn'
         value = 'Register New User'></td></tr>    
    </table>
</form>
</center>
<?php 
//CLEARS THE ERRORS ARRAY
$errors = array(); 
?>

行中:

else {
//SET COOKIE, EXPIRE IN 600 SECONDS
setcookie("userid", $username, time()+600 );

您正在尝试在用户标识中分配名为 $username 的 var。但我在任何地方都看不到它。

如果它未定义,那么您的问题在哪里。