jQuery Real Person - 总是失败


jQuery Real Person - always fails

无论我输入什么(即使是正确的验证码),我总是得到不匹配的输出。我尝试回显这些值(如果您输入正确的代码,它们应该匹配)。我总是得到这样的东西:


6952304285049-1247767175

  • 我正在使用jquery-1.10.2.min.js(并将其与realperson.js文件一起链接到我的标头中)http://gfishdesigns.com/COMP2920/_COMPLETED/Assignment%202/SignUp.php

这是我的代码(我也在做一些其他验证):

<?php
include 'Header.php';
include 'Database.php';
?>
<script type="text/javascript">
    $(function() {
        $('#defaultReal').realperson();
    });
</script>
<h1>Sign Up</h1>
<?php
if ($_POST){
    $username = $_POST['username'];
    $password = $_POST['password'];
    $check = '';
    //validate CAPTCHA
    function rpHash($value) { 
        $hash = 5381; 
        $value = strtoupper($value); 
        for($i = 0; $i < strlen($value); $i++) { 
        $hash = (($hash << 5) + $hash) + ord(substr($value, $i)); 
        } 
        return $hash; 
    } 
      if (rpHash($_POST['defaultReal']) == $_POST['defaultRealHash']) { ?>
        <p class="accepted">You have entered the "real person" value correctly and the form has been processed.</p>
<?php 
    //if username is not blank
    if($username != ''){
        //check if username exists already
        $query = "SELECT username FROM tbl_user;";
        $result = mysql_query($query) or die(mysql_error());
        while ($record = mysql_fetch_row($result))
        {
            foreach($record as $field)
            {
                if($field == $username){
                    //if user exists, dont let them add same user
                    $error_message_username = 'username already used; choose a unique name';
                }
                else{
                    $check = 'pass';
                }
            }
        }   
    }else{
        $error_message_username = 'username cannot be blank';
    }
    //if password is not blank
    if($password != ''){    
        $error_message_password = '';
        // encrypt password
        $encrypted_password = md5($password);   
        if($check == 'pass'){
            //set username and password into database
            $query = "INSERT INTO tbl_user VALUES('','".$username."','".$encrypted_password."');";
            $result = mysql_query($query) or die(mysql_error());
        }
    }else{
        $error_message_password = 'password cannot be blank';
    }

    } else { ?>
            <p class="rejected">You have NOT entered the CAPTCHA value correctly and the form has been rejected.</p>
    <?php 
echo rpHash($_POST['defaultReal']) . '<br/>';
echo $_POST['defaultRealHash'];
}
}    
?>
<form method="post" action="SignUp.php">
  <p>
    E-Mail:
    <input type="text" class="required email" id="username" name="username">
    <?php 
    if ( $error_message_username != '' ) {
        print "$error_message_username";
    }
    ?>
  </p>
  <p>
    Password:
    <input type="text" name="password">
            <?php 
    if ( $error_message_password != '' ) {
        print "$error_message_password";
    }
    ?>
  </p>
  <p>
    CAPTCHA:
    <input type="text" id="defaultReal" name="defaultReal">
  </p>
  <p>
    <button class="mybutton" type="submit" value="Sign Up">Sign Up</button>
  </p>
</form>

雷格·雅各布斯说得好,这是你指出的同一个问题。我也面临同样的事情,并通过如下所示的更改来解决:

function rpHash($value) {
    $hash = 5381;
    $value = strtoupper($value);
    for($i = 0; $i < strlen($value); $i++) {
        $hash = (leftShift32($hash, 5) + $hash) + ord(substr($value, $i));
    }
    return $hash; }
function leftShift32($number, $steps) {
    $binary = decbin($number);
    $binary = str_pad($binary, 32, "0", STR_PAD_LEFT);
    $binary = $binary.str_repeat("0", $steps);
    $binary = substr($binary, strlen($binary) - 32);
    return ($binary{0} == "0" ? bindec($binary) :
        -(pow(2, 31) - bindec(substr($binary, 1)))); 
}
if (isset($_POST['submit'])) {
    .....
    if (rpHash($_POST['defaultReal']) != $_POST['defaultRealHash']) {
        echo "Invalid contact request, please try again with correct verification code...";
        exit;
    }
    .....
    .....
}

希望它也能帮助其他人。

提供了两个版本的php rpHash函数,一个用于32位,一个用于64位PHP。 运行 phpinfo 并确保你使用的是本页 http://keith-wood.name/realPerson.html 中提供的函数的正确版本。 此处使用的按位函数将在 32 位和 64 位计算机上返回不同的值。 请参阅此页面: http://www.php.net/manual/en/language.operators.bitwise.php