我正在研究来自 wunderground.com 的json源代码。作为文档中显示的示例代码。我可以调整和锻炼一些简单的格式。但我被这个困住了。我试图用谷歌搜索每个地方,但没有解决方案。
下面是示例代码:
<?php
$json_string = file_get_contents("http://api.wunderground.com/api/b8e924a8f008b81e/geolookup/conditions/q/IA/Cedar_Rapids.json");
$parsed_json = json_decode($json_string);
$location = $parsed_json->{'location'}->{'city'};
$temp_f = $parsed_json->{'current_observation'}->{'temp_f'};
echo "Current temperature in ${location} is: ${temp_f}'n";
?>
好吧,我需要一些信息,例如 pws/车站的"锡达拉皮兹":
"pws": {
"station": [
{
"neighborhood":"Ellis Park Time Check",
"city":"Cedar Rapids",
"state":"IA",
"country":"US",
"id":"KIACEDAR22",
"lat":41.981174,
"lon":-91.682632,
"distance_km":2,
"distance_mi":1
}
]
}
(您可以通过单击此:http://api.wunderground.com/api/b8e924a8f008b81e/geolookup/conditions/q/IA/Cedar_Rapids.json 获取所有代码)现在的问题是:
- 这些数据叫什么?(数组,数组中的数组?
- 我怎样才能把这些数据从生产线中提取出来?
问候
station
是pws
对象中的一个数组。
要获取数据,您可以执行以下操作:
<?php
$json_string = file_get_contents("http://api.wunderground.com/api/b8e924a8f008b81e/geolookup/conditions/q/IA/Cedar_Rapids.json");
$parsed_json = json_decode($json_string);
$location = $parsed_json->{'location'}->{'city'};
$temp_f = $parsed_json->{'current_observation'}->{'temp_f'};
echo "Current temperature in ${location} is: ${temp_f}'n";
$stations = $parsed_json->{'location'}->{'nearby_weather_stations'}->{'pws'}->{'station'};
$count = count($stations);
for($i = 0; $i < $count; $i++)
{
$station = $stations[$i];
if (strcmp($station->{'id'}, "KIACEDAR22") == 0)
{
echo "Neighborhood: " . $station->{'neighborhood'} . "'n";
echo "City: " . $station->{'city'} . "'n";
echo "State: " . $station->{'state'} . "'n";
echo "Latitude: " . $station->{'lat'} . "'n";
echo "Longitude: " . $station->{'lon'} . "'n";
break;
}
}
?>
输出:
Current temperature in Cedar Rapids is: 38.5
Neighborhood: Ellis Park Time Check
City: Cedar Rapids
State: IA
Latitude: 41.981174
Longitude: -91.682632