已解决<lt<
我一直忙于创建我的CMS,却被一个函数卡住了,这个函数给了我这个错误:
致命错误:在第40行上对E:''Xampp''htdocs''CMS_PF''includes''functions''functions.php中的非对象调用成员函数query()
它对应于脚本的这一部分:
function isUserAdmin($email){
global $mysqli;
$acces_admin = 3;
$query = "SELECT access FROM user WHERE email='$email'";
$result = $mysqli->query($query);
while($row = mysqli_fetch_assoc($result)) {
$user_access = $row['access'];
if($user_access == 3){
return true;
}
}
}
错误来自$result行。
我不知道它为什么会出现这个错误,希望有人能帮我指出
提前感谢,雷米。
尝试这个
function isUserAdmin($email){
global $mysqli;
$acces_admin = 3;
$query = "SELECT access FROM user WHERE email='$email'";
$result = mysqli_query($conn,$query);//where $conn is your database connection
while($row = mysqli_fetch_assoc($result)) {
$user_access = $row['access'];
if($user_access == 3){
return true;
}
}
}
mysqli_query($con,"SELECT*FROM Persons");mysqli_query($con,"INSERT INTO Persons(FirstName,LastName,Age)
问题解决了,忘记在特定页面上包含我的连接手掌