我想做的是使用PHP在一个单独的页面上显示用户输入，但当我处理表单时，没有显示任何输入值。我不得不使用javascript进行输入验证，这很好，但PHP页面不起作用。这是我的代码：HTML和Javascript
survey.hp:
<!DOCTYPE html>
<html>
<head>
<title>Survey Page</title>
<link rel="stylesheet" type="text/css" href="mystylepage.css" />
<script type="text/javascript">
function validate()
{
if (document.information.name.value == "" )
{
alert("Please provide your name!" );
document.information.value.focus();
return false;
}
if (document.information.email.value == "")
{
alert("Please provide an email!");
document.information.value.focus();
return false;
}
if (document.information.major.value == false)
{
alert("Please enter your major");
document.information.value.focus();
return false;
}
return true;
}
</script>
</head>
<div id="bodycolor">
<body>
<div id="container">
<div id="menu">Menu:
<a class="menu" href="index.htm">Home</a> | <a class="menu"
`href="faculty.htm">Faculty</a> |
<a class="menu" href="courses.htm">
Courses</a> | <a class="gradecalculator" href="gradecalculator.htm">Grade
Calculator</a> | <a class="survey" href="survey.htm">Survey</a>
</div>
</div>
<div id="header">
<h1><center>CSE Center for Health Information Technology</center></h1>
<br>
<div id="links">
<center><a href="https://www.kennesaw.edu/"><img src="KSU Logo.jpg"
alt="Logo" style="width:100px;height:100px;" /></a></center>
<br>
<center><a href="http://ccse.kennesaw.edu/">College of Computing and
Software Engineering</a></center>
</div>
</div>
<h1>Please enter you information below</h1>
<form name="information" method="POST" action="action.php"
onsubmit="return
validate();">
<table width="500" border="0">
<tr>
<td width="150" bgcolor="#99CCFF"><strong>Name</strong></td>
<td><input type="text" name="name" size="20" maxlength="20" /></td>
</tr>
<tr>
<td bgcolor="#99CCFF"><strong>Email</strong></td>
<td><input type="text" name="email" size="20" maxlength="20" /></td>
</table>
<p> Major:
<input name="major" type="radio" value="Information Technology" />
Information Technology
<input name="major" type="radio" value="Software Engineering" />
Software Engineering
<input name="major" type="radio" value="Computer Science" />
Computer Science</p>
<p>
<input type="submit" value="Process" />
</p>
<p id="msg"></p>
</form>
</body>
</html>
这是PHP页面：
action.php
<!DOCTYPE html>
<html>
<head>
<title>Survey Information Processing</title>
</head>
<body>
<h1>Form data</h1>
<p>Name: <?php echo $_POST["name"]?></p>
<p>Email: <?php echo $_POST["email"]?</p>
<p>Major: <?php echo $_POST["major"]?</p>
</body>
</html>
我是PHP的新手，所以非常感谢您的帮助！
您的表单方法应该是POST。
<form name="information" method="POST" action="action.php" onsubmit="return validate();">
并在提交按钮中添加一个名称：
<input type="submit" value="Process" name="submit" />
此外，如果条件为：，则可以添加此项
<?php
echo "<pre>";
print_r($_POST); // Check if you're getting any POST data
echo "</pre>";
?>
<?php if (isset($_POST['name'])) { ?>
<h1>Form data</h1>
<p>Name: <?php echo $_POST["name"]; ?>
</p>
<p>Email: <?php echo $_POST["email"]; ?>
</p>
<p>Major: <?php echo $_POST["major"]; ?>
</p>
<?php } ?>
希望这能有所帮助。
所以问题是你的方法是get，但你试图通过后访问
更改
method="GET"
至
method="POST"
在您的表单上。