如何在不指定基类名称的情况下从子基类静态方法引用基类的父类

在PHP中，我想从子类调用父类的父类中的静态方法，而不引用父类名称的父类（请参阅下面代码中的注释）：

class Base {
  public static function helloStatic() {
    return "Hello base!'n";
  }
}
class Foo extends Base {
  private $fooMember;
  public static function helloStatic() {
    return "Hello foo!'n";
  }
  private function __construct() {
    $this->fooMember = "hello";
  }
  public function getFooMember() {
    return $this->fooMember;
  }
}
class Bar extends Foo {
  private $barMember;
  public static function helloStatic() {
    // I want to write the equivalent of:
    //echo Base::helloStatic();
    // here *without specifying any class names*
    echo get_parent_class(get_parent_class())::helloStatic();
  }
}
echo Bar::helloStatic();

预期输出：

Hello base!

输出：

<br />
<b>Parse error</b>:  syntax error, unexpected T_PAAMAYIM_NEKUDOTAYIM, expecting ',' or ';' on line <b>45</b><br />