我有一组intime和outtime，我想计算intime和out之间的持续时间，并将所有持续时间相加，得到总持续时间
示例：
Array
(
[1] => Array
(
['intime'] => 1342086993
['outime'] => 1342087585
)
[3] => Array
(
['intime'] => 1342087669
['outtime] => 1342096165
)
[5] => Array
(
['intime'] => 1342096339
['outime'] => 1342096345
)
)
$total_duration = 0;
foreach($logArray as $log)
{
$duration = $log['outime'] - $log['intime'];
$total_duration += $duration;
}
$duration_hrs = $total_duration/3600;
echo 'Time spend in hrs :'.$duration_hrs;
但这并没有给我合适的持续时间。还有其他方法吗？
使用array_map首先将每个元素映射到持续时间，然后使用array_sum对它们求和：
$durations = array_map(function ($e) {
return $e['outtime'] - $e['intime'];
}, $logArray);
$total_duration = array_sum($durations);
您的无语法脚本，对我来说很好：
<?php
$logArray = Array (
1 => Array (
'intime' => 1342086993,
'outime' => 1342087585
),
3 => Array (
'intime' => 1342087669,
'outime' => 1342096165
),
5 => Array (
'intime' => 1342096339,
'outime' => 1342096345
)
);
$total_duration = 0;
foreach( $logArray as $log ) {
$duration = $log[ 'outime' ] - $log[ 'intime' ];
$total_duration += $duration;
echo $duration / 3600 . "<br />";
}
$duration_hrs = $total_duration / 3600;
echo 'Time spend in hrs: ' . $duration_hrs;
?>
输出：
0.16444444444444
2.36
0.0016666666666667
Time spend in hrs: 2.5261111111111
似乎您的时间格式不正确：对于，13, July 2012 04:04:32 PM应该是13. July 2012 04:04:32 PM
strtotime('13. July 2012 04:04:32 PM')
正确工作。它应该给1342195472而不是给你1342168834。因此，请检查生成错误微时间的时间格式
$total_duration = 0;
foreach($logArray as $log)
{
$duraton = $log['outtime'] - $log['intime'];
$total_duration += $duration;
}
$duration_hrs = $total_duration/3600;
echo 'Time spend in hrs :'.$duration_hrs;
您的代码中有一个简单的拼写错误。检查：
duraton vs duration
改变，一切都会好起来的。