我不知道如何使用PHP从.dat文件中检索单独的数据行（例如，名字、年龄、出生年份、性别）。我被网上读到的所有东西弄糊涂了。我需要从.dat文件中提取每一行的文本，并为每一行分配自己的$variable，以便稍后用于打印。到目前为止我所拥有的。
<?php
$personalinfo = fopen("personaldata.dat", "r");
$firstname = <!-- line one of .dat file -->;
$age = <!-- line two of .dat file -->;
$birthyear = <!-- line three of .dat file -->;
$sex = <!-- line four of .dat file -->;
$weight = <!-- line five of .dat file -->;
fclose($personalinfo);
print("<p> $firstname you are $age years old, born in $birthyear, you are $weight lbs. and $sex.</p>")
?>
Dat文件格式
.dat文件有多种格式。首先，您必须确定数据在.dat文件中的格式。听起来你是在说文件是行分隔的（每一行都代表一个值。）
访问文件行（文件功能）
PHP使得一次获取一行文件资源变得很容易，因为file函数返回由文件行组成的数组：
<?php
$personalinfo = file("personaldata.dat");
$firstname = $personalinfo[0];
$age = $personalinfo[1];
$birthyear = $personalinfo[2];
$sex = $personalinfo[3];
$weight = $personalinfo[4];
print("<p> $firstname you are $age years old, born in $birthyear, you are $weight lbs. and $sex.</p>");
访问文件行（老派）
<?php
$personalinfo = fopen("personaldata.dat", "r");
$firstname = fgets($personalinfo);
$age = fgets($personalinfo);
$birthyear = fgets($personalinfo);
$sex = fgets($personalinfo);
$weight = fgets($personalinfo);
fclose($personalinfo);
print("<p> $firstname you are $age years old, born in $birthyear, you are $weight lbs. and $sex.</p>");