如何从数据库中的两个表(用户和帖子）中为ionic创建api

我想制作一个api（我使用laravel 4.2作为后端）来使用ionic应用程序。例如：

//我赚了以下$游客：

                    $tourists = User::where('block','0')
                          ->where('guider', 1)
                           ->where('location', $location)
                           ->orderBy($orderBy, 'desc')
                           ->orderBy('updated_at', 'desc')
                           ->get(); 
                 return View::make('frontend.data.touristsData',array('tourists'=>$tourists)); 

//游客数据：

    <?php
  echo json_encode($tourists);

//在我的app.js（ionic）中使用过：

.controller('listController', ['$scope','$http','$state','$ionicModal', function($scope, $http, $state,$ionicModal){
    $http.get("./touristsData").success(
         function(data){
            $scope.tourists = data;
......

//用于html

<div>{{tourists.username}}: {{tourists.intro}}</div>

//以上是一张表

但是如果我有两个表，例如，users表和posts表

//用户表（laravel迁移）

            $table -> increments('id');//id auto_increment
        $table -> string('username',30);
        $table -> string('email',60) -> unique();
        $table -> string('password',64);
        $table -> boolean('admin')->default(0);
        $table -> boolean('block')->default(0);
        $table -> integer('tradeTime');
        $table -> string('nationality', 50);

//岗位表

            $table->increments('id');
        $table -> integer('needHour');

        $table -> string('travelDestination',40);
        $table -> text('intro',300);
        $table -> string('otherWords', 100);
        $table->integer('user_id');
        $table->softDeletes();   
        $table ->timestamps(); 

//user.php

    <?php
use Illuminate'Auth'UserTrait;
use Illuminate'Auth'UserInterface;
use Illuminate'Auth'Reminders'RemindableTrait;
use Illuminate'Auth'Reminders'RemindableInterface;
class User extends Eloquent implements UserInterface, RemindableInterface {
    use UserTrait, RemindableTrait;
    /**
     * The database table used by the model.
     *
     * @var string
     */
    protected $table = 'users';
       protected $guard = array('email', 'password');
    /**
     * The attributes excluded from the model's JSON form.
     *
     * @var array
     */
    protected $hidden = array('password', 'remember_token');

    public function posts(){
        return $this->hasMany('Posts');
    }

//post.php

    <?php
use Illuminate'Database'Eloquent'SoftDeletingTrait;
class post extends Eloquent{
   use SoftDeletingTrait;
   protected $dates = ['deleted_at'];
  protected $fillable = ['needHour', 'travelDestination','intro','otherWords'];

  public function user()
  {
    return $this->belongsTo('User');
  }
}

我们可以看到user_id将users表和posts表相互链接，所以我的问题是，我们如何输出两个表的内容，就像上面一样，只有一个表可以输出（这很容易）？

我想要实现的是如下代码：

<div>{{tourists.username}} : {{tourists.travelDestination}}</div>