如何更改此函数，使其仅打印分钟单位？
我的意思是：
现在是
This was 7 second ago
-- Couple minutes later --
This was 5 minute 8 second ago
但我想要这个：
This was 7 second ago
-- Couple minutes later --
This was 5 minute ago ( i dont care about the seconds )
此外，我如何检查它是否为复数？所以它会在单元后面加一个S？
功能：
function humanTiming($time)
{
$time = time() - $time; // to get the time since that moment
$tokens = array (
31536000 => 'year',
2592000 => 'month',
604800 => 'week',
86400 => 'day',
3600 => 'hour',
60 => 'minute',
1 => 'second'
);
$result = '';
$counter = 1;
foreach ($tokens as $unit => $text) {
if ($time < $unit) continue;
if ($counter > 2) break;
$numberOfUnits = floor($time / $unit);
$result .= "$numberOfUnits $text ";
$time -= $numberOfUnits * $unit;
++$counter;
}
return "This was {$result} ago";
}
这里有一种使用DateTime类（函数取自Glavić的答案）的方法：
function human_timing($datetime, $full = false) {
$now = new DateTime;
$ago = new DateTime('@'.$datetime);
$diff = $now->diff($ago);
$diff->w = floor($diff->d / 7);
$diff->d -= $diff->w * 7;
$string = array(
'y' => 'year',
'm' => 'month',
'w' => 'week',
'd' => 'day',
'h' => 'hour',
'i' => 'minute',
's' => 'second',
);
foreach ($string as $k => &$v) {
if ($diff->$k) {
$v = $diff->$k . ' ' . $v . ($diff->$k > 1 ? 's' : '');
} else {
unset($string[$k]);
}
}
if (!$full) $string = array_slice($string, 0, 1);
return $string ? implode(', ', $string) . ' ago' : 'just now';
}
示例：
echo human_timing(time() - 20);
echo human_timing(time() - 1000);
echo human_timing(time() - 5500);
输出：
20 seconds ago
16 minutes ago
1 hour ago
演示
查看PHP Date-Time类，您应该使用它，而不是手动操作。
更换此
$numberOfUnits = floor($time / $unit);
有了这个
$numberOfUnits = floor($time / $unit);
If ( (int) $numberOfUnits > 1 )
{
$text .= 's';
}
它可能是多的解决方案