警告:ftp_put()要求参数1为resource,在中给定布尔值


Warning: ftp_put() expects parameter 1 to be resource, boolean given in

我正在尝试制作一个表单,上传几个字段和3个图像。图像将通过FTP上传,当php上传到远程服务器时,使用FTP_connect()连接到FTP时出现问题。当php位于共享主机中时,它无法连接到服务器。但是当php在localhost中时,它不会显示任何错误。我现在正试图在Localhost上实现这一点,并首先将图像ftp_put到远程服务器中,以隔离错误。现在我犯了这个错误。

Warning: ftp_put() expects parameter 1 to be resource, boolean given in line 69

哪个是ftp_put($login,"abc.info/$photo",$_FILES["file"]["tmp_name"][$i],FTP_ASCII)

<?php
ini_set('display_errors', 1); error_reporting(E_ALL);
ob_start();
session_start();
include 'connect.php';
include 'Agentftpconnect.php';
if(!isset($_SESSION['username']))
{
    header("Location: home.php");
    exit;
}

if ($_POST)
{
 //get form data

 $Listingname = addslashes(strip_tags($_POST['Listingname']));
 $Location = addslashes(strip_tags($_POST['Location']));
 $nobed = addslashes(strip_tags($_POST['nobed']));
 $zip = addslashes(strip_tags($_POST['zip']));
 $price = ($_POST['price']);

 if (!$Listingname||!$nobed||!$Location||!$zip||!$price)
    die ("Please fill out all fields"); 
    else 

    for($i=0;$i<3;$i++)
    {

if ((($_FILES["file"]["type"][$i] !== "image/gif")
|| ($_FILES["file"]["type"][$i] !== "image/jpeg")
|| ($_FILES["file"]["type"][$i] !== "image/jpg")
|| ($_FILES["file"]["type"][$i] !== "image/pjpeg")
|| ($_FILES["file"]["type"][$i] !== "image/x-png")
|| ($_FILES["file"]["type"][$i] !== "image/png"))
    && ($_FILES["file"]["size"][$i] > 400000))
die("File is not correct");
else{
  if ($_FILES["file"]["error"][$i] > 0)
    {
    echo "Return Code: " . $_FILES["file"]["error"][$i] . "<br>";
    }
  else
    {
    echo "Upload: " . $_FILES["file"]["name"][$i] . "<br>";
    echo "Size: " . ($_FILES["file"]["size"][$i] / 1024) . " kB<br>";
    echo "Temp file: " . $_FILES["file"]["tmp_name"][$i] . "<br>";
    echo "<br>";
    if (file_exists("abc.info/rent" . $_FILES["file"]["name"][$i]))
      {
      die($_FILES["file"]["name"][$i] . " already exists please add another file, or change the name ");
      }
    else
      {
        $photo=$_FILES["file"]["name"][$i];
      ftp_put($login,"abc.info/$photo",$_FILES["file"]["tmp_name"][$i],FTP_ASCII) or die("Can not upload");
      echo "Stored in: " . "abc.info/rent/" . $_FILES["file"]["name"][$i];
      }
    }
}

}
    {
      $photo0=$_FILES["file"]["name"][0];
        $photo1=$_FILES["file"]["name"][1];
         $photo2=$_FILES["file"]["name"][2];
       $username=$_SESSION['username'];
           //register into database
            mysqli_query($con,"INSERT INTO Listing (username,Listingname,Location,nobed,zip,price,pic1,pic2,pic3) VALUES 
                ('$username','$Listingname','$Location','$nobed','$zip','$price','$photo0','$photo1','$photo2');") or die(mysqli_error());

            echo "Listing Added";
    }        
       }


else
{
?>
<form action="Submitlisting8.php" method="post"
enctype="multipart/form-data">
Listing Name:<br />
<input type='text' name='Listingname'><p />
Location:<br />
<input type='text' name='Location'><p />
Number of Beds:<br />
<input type='test' name='nobed'><p />
Zip:<br />
<input type='text' name='zip'><p />
Price:<br />
<input type='text' name='price'><p />

<label for="file">Pic1(File must be exceed 4mb):</label>
<input type="file" name="file[]" id="file[]"><br>
<label for="file">Pic2(File must be exceed 4mb):</label>
<input type="file" name="file[]" id="file[]"><br>
<label for="file">Pic3(File must be exceed 4mb):</label>
<input type="file" name="file[]" id="file[]"><br>
<br>
<input type='submit' name='submit' value='Submit'>
</form>
<FORM METHOD="LINK" ACTION="agentaccount.php">
<INPUT TYPE="submit" VALUE="Back to Account">
</form>
<?php
}

?>

FTPconnect

<?php
$ftp_user_name='name';
$ftp_user_pass='pass';
$connection = 'ftp.abc.info';
$connect = ftp_connect($connection) or die("Couldn't connect to $connection"); 
$login=ftp_login($connect, $ftp_user_name, $ftp_user_pass);
if(!$login)
{
    die("But failed at login Attempted to connect to $connection for user $ftp_user_name....");
}

?>

ftp_put()需要使用ftp_connect()获得的有效资源。如果您看到此错误消息,则您对ftp_connect()的呼叫失败。您需要使用ftp_connect()获得一个有效的资源,如果不能,您需要弄清楚是什么原因导致脚本无法连接到远程主机,因为这是问题的根本原因。

为了防止脚本失败,您应该将FTP尝试封装在if语句中,该语句检查ftp_connect()是否成功连接:

if (($resource = ftp_connect($host)) !== false) {
    // do FTP stuff
}