我的联系人页面中有这段代码。
<script src="js/jquery-1.9.1.min.js"></script>
<script src="js/main.js"></script>
<script>
jQuery(document).ready(function() {
$("#submit").click(function()
{
var pattern = /^[a-zA-Z0-9'-_]+('.[a-zA-Z0-9'-_]+)*@[a-z0-9]+('-[a-z0-9]+)*('.[a-z0-9]+('-[a-z0-9]+)*)*'.[a-z]{2,4}$/;
//var pn = /^('+91-|'+91|0)?'d{10}$/;
var email = $("#email").val();
var message = $("#message").val();
var subject = $("#subject").val();
var name = $("#name").val();
if(name=="")
{
//$('#empty1').show(1).delay(5000).fadeOut();
$('#name').focus();
return false;
}
else if(message=="")
{
//$('#empty4').show(1).delay(5000).fadeOut();
$('#message').focus();
return false;
}
else if(subject=="")
{
//$('#empty4').show(1).delay(5000).fadeOut();
$('#subject').focus();
return false;
}
else if(!(pattern.test(email)))
{
//$('#error2').show(1);
$('#email').focus();
}
else if(email=="")
{
//$('#empty2').show(1).delay(5000).fadeOut();
$('#email').focus();
return false;
}
else
{
var dataString = 'name='+ name + '&email=' + email + '&message=' + message + '&subject=' + subject;
$.ajax({
type: "POST",
url: "mail.php",
data: dataString,
success: function(){
//$('.success').show('slide').delay(5000).fadeOut();
$("#contact-form")[0].reset();
alert("Your Detail Is Submitted, We Will Connect With You Soon.");
}
});
}
return false;
});
});
我有这样的状态。
<form class="b-form b-contact-form m-contact-form" action="" style="margin-bottom: 10px;" id="contact-form">
<div class="input-wrap">
<i class="icon-user"></i>
<input class="field-name" type="text" placeholder="Name (required)" name="name" id="name">
</div>
<div class="input-wrap">
<i class="icon-envelope"></i>
<input class="field-email" type="text" placeholder="Email (required)" name="email" id="email">
</div>
<div class="input-wrap">
<i class="icon-pencil"></i>
<input class="field-subject" type="text" placeholder="Subject" name="suject" id="subject">
</div>
<div class="textarea-wrap">
<i class="icon-pencil"></i>
<textarea class="field-comments" placeholder="Message" name="message" id="message"></textarea>
</div>
<input class="btn-submit btn colored" type="submit" value="Submit Comment" id="submit" name="submit">
</form>
我还有ajax mail.php页面。
<?php
$to = "demo@example.com";
$subject = $_REQUEST["subject"];
$message = "message=".$_REQUEST["message"]."<br />";
$message .= "name=".$_REQUEST["name"]."<br />";
$message .= "email=".$_REQUEST["email"];
$headers = "MIME-Version: 1.0" . "'r'n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "'r'n";
$headers .= "From:" .$_REQUEST["email"]. "'r'n";
mail($to,$subject,$message,$headers);
?>
我完成了服务器邮件转发设置,还检查了ajax调用,以及它将解析哪些数据。使用控制台弹片。但我的电子邮件id无法接通邮件。请帮帮我,我现在能做什么?
在这里,请尝试一下。
您的消息变量格式不正确,我对您的标题进行了一些修改。
这对我有效,减去你的jQuery方法。
<?php
$to = "demo@example.com";
$name = $_REQUEST['name'];
$email = $_REQUEST['email'];
$subject = $_REQUEST['subject'];
$message = $_REQUEST['message'];
$message .= "" . "<br/>";
$message .= "name= $name" . "<br/>";
$message .= "email= $email" . "<br/>";
$headers = "MIME-Version: 1.0" . "'r'n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "'r'n";
$headers .= "From: $email" . "'r'n" .
"Reply-To: $email" . "'r'n" .
"X-Mailer: PHP/" . phpversion();
if(mail($to,$subject,$message,$headers)){
echo "Success!!";
}
else {
echo "Sorry.";
}
?>