从当前日期开始计算接下来的6天

这里有一个不直接依赖于自己计算的：

$days=[]；$period=新DatePeriod(new DateTime（），//期间的开始日期new DateInterval（'1D'），//将时间间隔定义为1天的时段6//在开始日期之前应用间隔6次)；foreach（$period表示$day）{$days[]=$day->格式（'l'）；}

有很多方法可以提到一些样本，如下所示：

1）使用循环中的strtotime函数和临时$date变量

$date = date('Y-m-d'); //today date
$weekOfdays = array();
for($i =1; $i <= 7; $i++){
    $date = date('Y-m-d', strtotime('+1 day', strtotime($date)));
    $weekOfdays[] = date('l : Y-m-d', strtotime($date));
}
print_r($weekOfdays);

2）使用strtotime函数和当前日期的+$i days

$date = date('Y-m-d'); //today date
$weekOfdays = array();
for($i =1; $i <= 7; $i++){
    $weekOfdays[] = date('l : Y-m-d', strtotime("+$i day", strtotime($date)));
}
print_r($weekOfdays);

3）使用DateTime类和modify方法

$date = date('Y-m-d'); //today date
$weekOfdays = array();
$date = new DateTime($date);
for($i=1; $i <= 7; $i++){
    $date->modify('+1 day');
    $weekOfdays[] = $date->format('l : Y-m-d');
}
print_r($weekOfdays);

4）使用DateTime类和DateInterval类

$date = date('Y-m-d'); //today date
$weekOfdays = array();
$date = new DateTime($date);
for($i=1; $i <= 7; $i++){
    $date->add(new DateInterval('P1D'));
    $weekOfdays[] = $date->format('l : Y-m-d');
}
print_r($weekOfdays);

5）使用DatePeriod、DateInterval和DateTime类

$date = date('Y-m-d', strtotime('+1 day')); //tomorrow date
$weekOfdays = array();
$begin = new DateTime($date);
$end = new DateTime($date);
$end = $end->add(new DateInterval('P7D'));
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $dt){
    $weekOfdays[] = $dt->format('l : Y-m-d');
}
print_r($weekOfdays);

今天是4月12日星期二，所以所有代码的输出将是：

Array
(
    [0] => Wednesday : 2016-04-13
    [1] => Thursday : 2016-04-14
    [2] => Friday : 2016-04-15
    [3] => Saturday : 2016-04-16
    [4] => Sunday : 2016-04-17
    [5] => Monday : 2016-04-18
    [6] => Tuesday : 2016-04-19
)

有关更多详细信息，请查看：

• strtotime
• 日期时间
• 日期间隔
• 日期周期

我认为您需要一个for循环：

$weekOfdays = array();
$day = date('l');
$weekOfdays[] = $day;
$day = strtotime($day);

for($i = 1; $i <= 6; ++$i) {
    $next = strtotime("+$i day",$day);
    $weekOfdays[] = date("l",$next);
} 

只需使用while循环每天进行调整。只需再添加一天+1:

$weekOfdays = array();
$date = time();
$next = strtotime('+6 days');
while ($date <= $next) { // loop until next six
    $weekOfdays[] = date('l', $date); // push the day name
    $date = strtotime('+1 day', $date); // add +1 on $date
}
print_r($weekOfdays);

使用strtotime函数和while-loop

$weekOfdays = array();
$current_date = time(); //get current date.
$next = strtotime('+6 days');
while ($current_date <= $next) { 
    $weekOfdays[] = date('l', $current_date); 
    $current_date = strtotime('+1 day', $current_date); // add next date
}
echo "<pre>";
print_r($weekOfdays);
echo "</pre>";

结果：

Array
(
    [0] => Friday
    [1] => Saturday
    [2] => Sunday
    [3] => Monday
    [4] => Tuesday
    [5] => Wednesday
    [6] => Thursday
)

这里有一个简单的修改代码，它将显示的总天数

<?php
$weekOfdays = array();
$day = date('l');
$weekOfdays[] = $day;
$day = strtotime($day);
$total_days='5';//you can increase or decrease the day to display
for($i=1;$i<=$total_days;$i++){
 $next = strtotime("+$i day",$day);
$weekOfdays[] = date("l",$next);
}
print_r($weekOfdays);
?>

它的

    Array ( 
[0] => Monday 
[1] => Tuesday 
[2] => Wednesday 
[3] => Thursday 
[4] => Friday 
[5] => Saturday )

$weekOfdays = array();
$date = date("l");// current day
for($i = 0; $i < 7; $i++) {
    $weekOfdays[] = date("l", strtotime($date . "+$i day")); 
}
var_dump($weekOfdays);

检查以下内容。此处数组获取包含当前日期的7天名称。

$weekOfdays = array();
for($i = 1,$nxtday = time(); $i<=7; $i++)
{
    $weekOfdays[] = date("l", $nxtday);
    $nxtday += 86400;
}
var_dump($weekOfdays);