我正试图使用oauthapi从pinterest获取用户配置文件。用户数据代码:
$me = $pinterest->users->me(array(
'fields' => 'username,first_name,last_name,image[large]'
));
和回波结果:
echo $me;
输出如下:
{"id":"195414208739840616","username":"rajivsharma033","first_name":"Rajiv","last_name":"Sharma","bio":null,"created_at":null,"counts":null,"image":{"large":{"url":"https:'/'/s-media-cache-ak0.pinimg.com'/avatars'/rajivsharma033_1459712414_280.jpg","width":280,"height":280}}}
现在我想把这个结果作为
id="195414208739840616"
username="rajivsharma033"
first_name="Rajiv"
等等。。。请帮帮我。
由于您正在获取json
数据,因此需要使用json_decode()
:-
<?php
$me = '{"id":"195414208739840616","username":"rajivsharma033","first_name":"Rajiv","last_name":"Sharma","bio":null,"created_at":null,"counts":null,"image":{"large":{"url":"https:'/'/s-media-cache-ak0.pinimg.com'/avatars'/rajivsharma033_1459712414_280.jpg","width":280,"height":280}}}';
$array_data = json_decode($me);
echo "<pre/>";print_r($array_data);
foreach ($array_data as $key=>$value){
if($key == 'image'){
echo $key. " url is=" . $value->large->url .'<br/>';
}else{
echo $key. "=" . $value .'<br/>';
}
}
我会使用两次foreach
:来解决它
$a = json_decode($me);
foreach ($a as $key=>$value){
echo $key.'="'.$value.'"<br/>';
}
foreach ($a['image']['large'] as $key=>value){
echo 'image-large-'$key.'="'.$value.'"<br/>';
}
或者,您可以递归地执行以下操作:
function echojson($string=''){
$a = json_decode($me);
foreach ($a as $key=>$value){
if (is_array($value)) echojson($string.'-'.$key);
else
echo $string.$key.'="'.$value.'"<br/>';
}
}