我在 3 个 PHP 文件中有一些require"链"。 index.php需要db_get.php，这就需要db_cred.php。它们都位于同一目录中。这些是代码：
索引.php
<?php
require 'db_get.php';
$db = getDatabase();
var_dump($db);
?>
db_get.php
<?php
require 'db_cred.php';
function getDatabase()
{
$host = 'localhost';
$database = $db_name;
$username = $db_user;
$password = $db_pass;
$connectionString = 'mysql:host=' . $host . '; dbname=' . $database . '';
$attributes = array(
'PDO::ATTR_ERRMODE => 'PDO::ERRMODE_EXCEPTION,
'PDO::ATTR_PERSISTENT => false,
'PDO::MYSQL_ATTR_INIT_COMMAND => 'set names utf8mb4'
);
return new 'PDO( $connectionString, $username, $password, $attributes);
}
?>
db_cred.php(此文件由另一个 PHP 文件自动生成(
<?php $db_name="testdb"; $db_user="qNOSdZ"; $db_pass="cAHk8A"; ?>
我从索引中得到的错误.php：
Notice: Undefined variable: db_name in C:'xampp'htdocs'sipil'me'db'db_get.php on line 7
Notice: Undefined variable: db_user in C:'xampp'htdocs'sipil'me'db'db_get.php on line 8
Notice: Undefined variable: db_pass in C:'xampp'htdocs'sipil'me'db'db_get.php on line 9
为什么我会收到这些错误？所有这些文件都位于同一目录中。我可能是哑巴，这个问题已经花了我一段时间了，请帮忙。
function getDatabase()
{
global $db_name;
global $db_user;
global $db_pass;
$host = 'localhost';
$database = $db_name;
$username = $db_user;
$password = $db_pass;
$connectionString = 'mysql:host=' . $host . '; dbname=' . $database . '';
$attributes = array(
'PDO::ATTR_ERRMODE => 'PDO::ERRMODE_EXCEPTION,
'PDO::ATTR_PERSISTENT => false,
'PDO::MYSQL_ATTR_INIT_COMMAND => 'set names utf8mb4'
);
return new 'PDO( $connectionString, $username, $password, $attributes);
}
如上述评论所述，解决方案应该是：
<?php
require 'db_cred.php';
function getDatabase()
{
global $db_name, $db_user, $db_pass;
$host = 'localhost';
$database = $db_name;
$username = $db_user;
$password = $db_pass;
$connectionString = 'mysql:host=' . $host . '; dbname=' . $database . '';
$attributes = array(
'PDO::ATTR_ERRMODE => 'PDO::ERRMODE_EXCEPTION,
'PDO::ATTR_PERSISTENT => false,
'PDO::MYSQL_ATTR_INIT_COMMAND => 'set names utf8mb4'
);
return new 'PDO( $connectionString, $username, $password, $attributes);
}
?>