当页面加载性别=3,如果单击女性按钮性别=1,如果单击男性按钮性别=2时,代码点火器模型返回json_encode
结果。现在,我想在if条件的旁边添加另一个where语句。如果条件为,则查看性别是否为3。
function get_data_all($gender, $age_min, $age_max) {
$counter = 0;
$this->db->select('*');
if($gender == 1){
$this->db->where('gender', 'F'); //working
$counter++;
}
elseif($gender == 2){
$this->db->where('gender', 'M'); //working
$counter++;
}
elseif($gender == 3){
$names = array('F', 'M');
$this->db->where_in('gender', $names); //working
$this->db->where('age>=', 12); //not working
$this->db->where('age<=', 18); //not working
$counter++;
}
else{
redirect(base_url());
}
$query = $this->db->get('sudent_details');
if (($query->num_rows() > 0) && ($counter > 0)){
echo(json_encode($query->result()));
$counter = 0;
} else {
return false;
}
}
在列名中添加空格&比较操作员
$this->db->where('age >= ', 12);
$this->db->where('age <= ', 18);
您需要替换以下行:
$this->db->where('age>=', 12); //not working
$this->db->where('age<=', 18); //not working
TO:
$this->db->where('age','>=',12);
$this->db->where('age','<=',18);
OR:
$this->db->where('age >= 12',FASLE,FALSE);
$this->db->where('age <= 18',FASLE,FALSE);
OR:
$this->db->where('age>=', 12,FALSE);
$this->db->where('age<=', 18,FALSE);
它应该起作用。