我需要合并表'fos_user'和'institution'。我需要显示来自两个实体的注册表。我对FOSUserBundle有问题。我在用户类中创建了新属性
/**
* @ORM'Id
* @ORM'Column(type="integer")
* @ORM'GeneratedValue(strategy="AUTO")
*/
protected $id;
protected $workPhone;
protected $adminPhone;
protected $name;
protected $adress;
public function __construct()
{
parent::__construct();
}
public function setAdress($adress)
{
$this->adress = $adress;
}
public function setName($name)
{
$this->name = $name;
}
public function setWorkPhone($workPhone)
{
$this->workPhone = $workPhone;
}
public function setAdminPhone($adminPhone)
{
$this->adminPhone = $adminPhone;
}
public function getName()
{
return $this->name;
}
public function getAdress()
{
return $this->adress;
}
public function getWorkPhone()
{
return $this->workPhone;
}
public function getAdminPhone()
{
return $this->adminPhone;
}
/**
* Get id
*
* @return integer
*/
public function getId()
{
return $this->id;
}
我有实体机构，我想合并它。
/**
* @var integer
*
* @ORM'Column(name="id_institution", type="integer")
* @ORM'Id
* @ORM'GeneratedValue(strategy="IDENTITY")
*/
private $idInstitution;
/**
* @var string
*
* @ORM'Column(name="name", type="string", length=45, nullable=false)
*/
private $name;
/**
* @var integer
*
* @ORM'Column(name="work_phone", type="integer", nullable=false)
*/
private $workPhone;
/**
* @var integer
*
* @ORM'Column(name="admin_phone", type="integer", nullable=true)
*/
private $adminPhone;
/**
* @var string
*
* @ORM'Column(name="adress", type="string", length=255, nullable=false)
*/
private $adress;
/**
* @var 'AppBundle'Entity'FosUser
*
* @ORM'ManyToOne(targetEntity="AppBundle'Entity'FosUser")
* @ORM'JoinColumns({
* @ORM'JoinColumn(name="id_fos_user", referencedColumnName="id")
* })
*/
private $idFosUser;
/**
* Get idInstitution
*
* @return integer
*/
public function getIdInstitution()
{
return $this->idInstitution;
}
/**
* Set name
*
* @param string $name
* @return Institution
*/
public function setName($name)
{
$this->name = $name;
return $this;
}
/**
* Get name
*
* @return string
*/
public function getName()
{
return $this->name;
}
/**
* Set workPhone
*
* @param integer $workPhone
* @return Institution
*/
public function setWorkPhone($workPhone)
{
$this->workPhone = $workPhone;
return $this;
}
/**
* Get workPhone
*
* @return integer
*/
public function getWorkPhone()
{
return $this->workPhone;
}
/**
* Set adminPhone
*
* @param integer $adminPhone
* @return Institution
*/
public function setAdminPhone($adminPhone)
{
$this->adminPhone = $adminPhone;
return $this;
}
/**
* Get adminPhone
*
* @return integer
*/
public function getAdminPhone()
{
return $this->adminPhone;
}
/**
* Set adress
*
* @param string $adress
* @return Institution
*/
public function setAdress($adress)
{
$this->adress = $adress;
return $this;
}
/**
* Get adress
*
* @return string
*/
public function getAdress()
{
return $this->adress;
}
/**
* Set idFosUser
*
* @param 'AppBundle'Entity'FosUser $idFosUser
* @return Institution
*/
public function setIdFosUser($idFosUser = null)
{
$this->idFosUser = $idFosUser;
return $this;
}
/**
* Get idFosUser
*
* @return 'AppBundle'Entity'FosUser
*/
public function getIdFosUser()
{
return $this->idFosUser;
}
这是InstitutionManager的属性，我想保存实体，这就像现在的服务：
public function createNewEntity($user)
{
$entity = new Institution();
$entity->setName($user->getName());
$entity->setAdminPhone($user->getAdminPhone());
$entity->setWorkPhone($user->getWorkPhone());
$entity->setAdress($user->getAdress());
$entity->setidFosUser($user->getId());
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
$em->flush();
}
并听到覆盖注册控制器：
public function registerAction()
{
$form = $this->container->get('fos_user.registration.form');
$formHandler = $this->container->get('fos_user.registration.form.handler');
$confirmationEnabled = $this->container->getParameter('fos_user.registration.confirmation.enabled');
$process = $formHandler->process($confirmationEnabled);
if ($process) {
$user = $form->getData();
$authUser = false;
if ($confirmationEnabled) {
$this->container->get('session')->set('fos_user_send_confirmation_email/email', $user->getEmail());
$route = 'fos_user_registration_check_email';
} else {
$authUser = true;
$route = 'fos_user_registration_confirmed';
}
$this->setFlash('fos_user_success', 'registration.flash.user_created');
$institutionManager = $this->container->get('institution_manager');
$institution = $institutionManager->createNewEntity($user);
$url = $this->container->get('router')->generate($route);
$response = new RedirectResponse($url);
if ($authUser) {
$this->authenticateUser($user, $response);
}
return $response;
}
return $this->container->get('templating')->renderResponse('FOSUserBundle:Registration:register.html.'.$this->getEngine(), array(
'form' => $form->createView(),
));
}
services.yml:
services:
institution_manager:
class: AppBundle'Lib'Manager'InstitutionManager
arguments: [ @doctrine.orm.default_entity_manager ]
您的InstitutionController未正确初始化。有一个setContainer方法，路由器调用它来设置容器。getDoctrine反过来需要容器，因此出现null对象错误。
一个简单的破解方法是自己调用setContainer方法：
$entity = new InstitutionController();
$entity->setContainer($this->container);
$entity->createNewEntity($user);
但这是一个黑客，你应该做一些重新设计。您所称的控制器根本不是控制器。这是一种服务，也许是一种工厂或经理。有点像FOS UserManager。
因此，请阅读如何定义服务：http://symfony.com/doc/current/book/service_container.html
这需要一些研究，但一旦你了解了这个过程，服务就会成为第二天性。您将把条令实体经理直接注入您的服务中。
class InstitutionManager
{
protected $entityManager;
public function __construct($entityManager)
{
$this->entityManager = $entityManager;
}
public function createNewEntity($user)
{
$entity = new Institution();
$entity->setName($user->getName());
$entity->setAdminPhone($user->getAdminPhone());
$entity->setWorkPhone($user->getWorkPhone());
$entity->setAdress($user->getAdress());
$entity->setidFosUser($user->getId());
$this->entityManager->persist($entity);
$this->entityManager->flush();
return $entity;
}
我会把服务交给你。实体管理器服务id为doctrine.orgm.default_entity_manager
你的控制器会看起来像：
$institutionManager = $this->get('institution_manager');
$institution = $institutionManager->create($user);
您还需要重新思考如何关联用户对象。userId的东西是否定的。你会想在$institution和$user之间建立一对一的关系。但这确实是一个不同的话题。
享受吧。