我有一个php/html，用户在其中输入一些值，然后使用mysqli和插入查询将这些值更新到数据库中。如果用户没有在任何文本框中输入任何内容，我希望出现一条消息，说信息不在那里，我已经尝试使用
if($ownerName == "" ){
echo("Missing Information!");
但它不会起作用。
这是我的php代码
<?php
include "connect.php";
if($_POST["submit"])
{
$ownerName = $_POST['OwnerName'];
$location = $_POST['Location'];
$phoneNumber = $_POST['PhoneNumber'];
if($ownerName == "" || $location == "" || $phoneNumber == ""){
echo("Missing Information!");
/*if(is_numeric($phoneNumber) ){
settype($phoneNumber, "integer");
}*/
$query = "INSERT INTO OWNER VALUES ('$ownerName','$location', $phoneNumber)";
if (!mysqli_query($con,$query))
{
die('Error: ' . mysqli_error($con));
}
echo "<script type='text/javascript'>alert('1 record added')</script>";
mysqli_close($con);
}
?>这是我的表格
<html><head><title>Connect to Database</title></head><body>
<font size="4"> Enter owner details</font><br><br>
<form action="update.php" method="post" >
Owner Name:<input type="text" name="OwnerName">
Location: <input type="text" name="Location">
Phone Number:<input type="text" name="PhoneNumber">
<input type="submit" name = "submit" value="Submit Value">
</form></body></html>试试这个：
if((!isset($ownerName)) || $ownerName == "" || (!isset($location)) || $location == "" || (!isset($phoneNumber)) || $phoneNumber == "")){
echo("Missing Information!");
/*if(is_numeric($phoneNumber) ){
settype($phoneNumber, "integer");
}*/
}
else{
$query = "INSERT INTO OWNER VALUES ('$ownerName','$location', $phoneNumber)";
if (!mysqli_query($con,$query))
{
die('Error: ' . mysqli_error($con));
}
echo "<script type='text/javascript'>alert('1 record added')</script>";
mysqli_close($con);
}
试试这个
从更改您的条件
if($ownerName == "" || $location == "" || $phoneNumber == ""){
echo("Missing Information!");
$query = "INSERT INTO OWNER VALUES ('$ownerName','$location', $phoneNumber)";
if (!mysqli_query($con,$query))
{
die('Error: ' . mysqli_error($con));
}
echo "<script type='text/javascript'>alert('1 record added')</script>";
mysqli_close($con);
}
至
if($ownerName == "" || $location == "" || $phoneNumber == ""){
echo("Missing Information!");
} else {
$query = "INSERT INTO OWNER VALUES ('$ownerName','$location', $phoneNumber)";
if (!mysqli_query($con,$query))
{
die('Error: ' . mysqli_error($con));
}
echo "<script type='text/javascript'>alert('1 record added')</script>";
mysqli_close($con);
}
<?php
include "connect.php";
if(isset($_POST["submit"]))
{
$ownerName = isset($_POST['OwnerName']) ? $_POST['OwnerName']: '';
$location = isset($_POST['Location']) ? $_POST['Location']: '';
$phoneNumber = isset($_POST['PhoneNumber']) ? $_POST['PhoneNumber']: '';
//preventing sql injection
/*
$ownerName = mysqli_real_escape_string($con, $ownerName);
$$location = mysqli_real_escape_string($con, $ownerName);
$$phoneNumber = mysqli_real_escape_string($con, $ownerName);
*/
if(empty($ownerName) || empty($location) || empty($phoneNumber)){
echo("Missing Information!");
/*if(is_numeric($phoneNumber) ){
settype($phoneNumber, "integer");
}*/
}else{
$query = "INSERT INTO OWNER VALUES ('$ownerName','$location', $phoneNumber)";
if (!mysqli_query($con,$query))
{
die('Error: ' . mysqli_error($con));
}
echo "<script type='text/javascript'>alert('1 record added')</script>";
}
mysqli_close($con);
?>
还可以尝试使用var_dump（$_POST）查看发送的内容。
编辑：
我已经更新了if/else语句，所以现在它应该可以工作了。此外，请确保您已启用错误报告：
<?php
// Turn off error reporting
error_reporting(0);
// Report runtime errors
error_reporting(E_ERROR | E_WARNING | E_PARSE);
// Report all errors
error_reporting(E_ALL);
// Same as error_reporting(E_ALL);
ini_set("error_reporting", E_ALL);
// Report all errors except E_NOTICE
error_reporting(E_ALL & ~E_NOTICE);
?>
试试这个
<?php
include "connect.php";
if($_POST["submit"])
{
$ownerName = $_POST['OwnerName'];
$location = $_POST['Location'];
$phoneNumber = $_POST['PhoneNumber'];}
if(empty($ownerName) && empty($location) && empty($phoneNumber))
{
echo("Missing Information!");}
/*if(is_numeric($phoneNumber) ){
settype($phoneNumber, "integer");
}*/
else{
$query = "INSERT INTO OWNER VALUES ('$ownerName','$location', $phoneNumber)";
if (!mysqli_query($con,$query))
{
die('Error: ' . mysqli_error($con));
}
echo "<script type='text/javascript'>alert('1 record added')</script>";
mysqli_close($con);
}
?>试试这个：
<?php
include "connect.php";
if($_POST["submit"])
{
$ownerName = $_POST['OwnerName'];
$location = $_POST['Location'];
$phoneNumber = $_POST['PhoneNumber'];
if($ownerName == "" || $location == "" || $phoneNumber == ""){
echo("Missing Information!");
}
else{
$query = "INSERT INTO OWNER VALUES ('$ownerName','$location', $phoneNumber)";
if (!mysqli_query($con,$query))
{
die('Error: ' . mysqli_error($con));
}
echo "<script type='text/javascript'>alert('1 record added')</script>";
}
mysqli_close($con);
}
?>
**Please replace your code from below code**
<?php
include "connect.php";
if($_POST["submit"])
{
$ownerName = $_POST['OwnerName'];
$location = $_POST['Location'];
$phoneNumber = $_POST['PhoneNumber'];
if($ownerName == "" || $location == "" || $phoneNumber == ""){
echo("Missing Information!");
} else {
// please replace your column name (`owner_name`, `location`, `phone_number`)
$query = "INSERT INTO OWNER (`owner_name`, `location`, `phone`) VALUES ('" . $ownerName . "', '" . $location. "', " . $phoneNumber. ")";
if (!mysqli_query($con, $query))
{
die('Error: ' . mysqli_error($con));
}
echo "<script type='text/javascript'>alert('1 record added')</script>";
mysqli_close($con);
}
}
?>
尝试使用empty()函数或isset()