我正在从MySQL数据库表actors&尝试将结果填充到HTML选择框中：
<?php
$query = "SELECT actor_name FROM actors";
$result = mysql_query($query) or die("<h1>Error - the query could not be executed</h1>'n");
$num_rows = mysql_num_rows($result);
$row = mysql_fetch_array($result);
print("<h3>Actors</h3>'n");
print($num_rows);
if($num_rows == 0){
print("<h3>No items are currently recorded in table Actors</h3>'n");
}
else{
print("<select id='"actors'" name='"actors'">'n");
for($i = 0; $i < $num_rows; $i++){
print("<option>$row[$i]</option>");
$row = mysql_fetch_array($result);
}
print("</select>");
}
?>
错误：
注意：未定义的偏移量：第16行上C:''examplep''htdocs''actors.php中的1
从数组中的第二条记录开始，我收到了一个未定义的偏移通知。当我添加isset复选框时，选择框只填充第一条记录。这表明我的查询有问题吗？我查了一下我的桌子，一共有113条记录。
如有任何帮助，我们将不胜感激。
我认为下面的代码看起来更好，工作也很好。
$query = "SELECT actor_name FROM actors";
$result = mysql_query($query) or die("<h1>Error - the query could not be executed</h1>'n");
$num_rows = mysql_num_rows($result);
print("<h3>Actors</h3>'n");
print($num_rows);
if($num_rows == 0)
{
print("<h3>No items are currently recorded in table Actors</h3>'n");
}
else
{
print("<select id='"actors'" name='"actors'">'n");
while ($row = mysql_fetch_array($result))
{
print("<option>$row[0]</option>");
)
print("</select>");
mysql_free_result($result);
}
$query = "SELECT actor_name FROM actors";
$result = mysql_query($query) or die("<h1>Error -
the query could not be executed</h1>'n");
$num_rows = mysql_num_rows($result);
$row = mysql_fetch_array($result);
-`--------^^^^^^ //**you are already fetching the array once`**
您使用$row = mysql_fetch_array($result);两次
for($i = 0; $i < $num_rows; $i++){
print("<option>$row[$i]</option>");
$row = mysql_fetch_array($result);
----------------^^^^//**remove this**
}
正确的循环是：
for($i = 0; $i < $num_rows; $i++){
print("<option>$row[$i]</option>");
}