我有一个模型技能.php。在*技能控制器中.php*我有由crud生成的操作创建方法
actionCreate(){
$model=new Skill;
}
当我将$model更改为$modelSkill时,它会显示错误。为什么?
public function actionCreate()
{
$model=new Skill;
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if(isset($_POST['Skill']))
{
$model->attributes=$_POST['Skill'];
if($model->save())
$this->redirect(array('view','id'=>$model->skill_id));
}
$this->render('create',array(
'model'=>$model,
));
}
更改为$modelSkill后
public function actionCreate()
{
$modelSkill=new Skill;
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($modelSkill);
if(isset($_POST['Skill']))
{
$modelSkill->attributes=$_POST['Skill'];
if($modelSkill->save())
$this->redirect(array('view','id'=>$modelSkill->skill_id));
}
$this->render('create',array(
'model'=>$modelSkill,
));
}
我想我发现了你的失败。可能是您在视图文件中也替换了它吗?如果是,您还需要更改此设置:
$this->render('create',array(
'model'=>$modelSkill,
));
对此:
$this->render('create',array(
'modelSkill'=>$modelSkill,
));
正如你在 Yii 文档中看到的,数组将被放入函数 extract() 中。