我收到PHP通知错误。这段代码在php5.3中运行良好，但后来我将php升级到了PHP7。我想做的是，从链接中获取URL，然后只显示URL附带的参数。这是代码。
index.php
<?php
require_once('bootstrap.php');
$bootstrap = new Bootstrap($_GET);
?>
bootstrap.php
<?php
class Bootstrap{
private $controller;
private $action;
private $request;
public function __construct($request){
$this->request = $request;
if($this->request['controller'] == ''){
$this->controller = "Home";
}
elseif($_GET($request['controller'])){
$this->controller = $this->request['controller'];
}
if($this->request['action'] == ''){
$this->action = "index";
} else{
$this->action = $this->request['action'];
}
echo "<br />$this->controller<br />$this->action";
}
?>
转到URL:localhost/myDir/index.php/abc/def的输出
注意：第8行/srv/http/myDir/bootstrap.php中的未定义索引：controller
注意：未定义的索引：第14行/srv/http/myDir/bootstrap.php中的操作
主页
索引
empty()测试。。。将为0的true，"0"，false，"，空数组（）…通知也不见了！…对其他if和数组索引也执行同样的操作！
if(empty($this->request['action'])) {
为了避免类似的警告，您还应该在方法、函数等中提供默认值：
function ($arg=FALSE, $arg2=TRUE, $arg3=5, ...) {
如果您的代码运行良好&问题只是删除通知错误，然后您可以在php脚本中使用error_reporting(0)。
添加error_reporting(0)作为php脚本中的第一条语句
测试是否已设置：isset($this->request['action'])isset($this->request['controller'])
像这样：
<?php
class Bootstrap{
private $controller;
private $action;
private $request;
public function __construct($request){
$this->request = $request;
foreach ($request as $key => $value) {
echo $key . " = " . $value;
}
if(isset($this->request['controller']) && $this->request['controller'] == ''){
$this->controller = "Home";
}
elseif(isset($this->request['controller']) && $_GET($request['controller'])){
$this->controller = $this->request['controller'];
}
if(isset($this->request['action']) && $this->request['action'] == ''){
$this->action = "index";
}
else{
$this->action = $this->request['action'];
}
echo "<br />$this->controller<br />$this->action";
}
?>