PHP未定义的索引/变量


PHP Undefined index/variable

第一行出现错误未定义索引:$pwd下面还有未定义的变量。请出示新代码谢谢!结局唾手可得。

$pwd = $_POST['$pwd'];              //Error undefined index: $pwd
if( strlen($pwd) < 8 ) {
        $error .= "Password too short! 
";
}                                     //This line undefined variable

在此处获取上面的错误******错误变量

if( strlen($pwd) > 20 ) {
        $error .= "Password too long! 
";
}
if( strlen($pwd) < 8 ) {
        $error .= "Password too short! 
";
}
if( !preg_match("#[0-9]+#", $pwd) ) {
        $error .= "Password must include at least one number! 
";
}

if( !preg_match("#[a-z]+#", $pwd) ) {
        $error .= "Password must include at least one letter! 
";
}

if( !preg_match("#[A-Z]+#", $pwd) ) {
        $error .= "Password must include at least one CAPS! 
";
}

if( !preg_match("#'W+#", $pwd) ) {
        $error .= "Password must include at least one symbol! 
";
}

if($error){
        echo "Password validation failure(your choice is weak): $error";
} else {
        echo "Your password is strong.";
}

再次感谢:D

使用$pwd = $_POST['pwd']; 而不是$pwd = $_POST['$pwd'];

$pwd=$_POST['$pwd'];

我想这应该是:

$pwd=$_POST['pwd']

但这取决于密码字段在表单中的名称。如果表单上的密码字段的名称是password,则将其设置为$_POST['password']

如果您有。。。

<input type="password" name="pwd">

然后在php脚本中,您应该将其称为

$pwd = $_POST["pwd"];

注意name属性。