我正在尝试创建一个简单的计算器(这可能非常简单,但找不到错误:(叹气*),所以当我点击提交时,数字1和数字2将执行用户选择的操作。但提交时答案不会得到回应:(问题出在哪里?非常感谢!
<?php
if ($_POST['subBtn']) {
$number1 = $_POST['number1'];
$number2 = $_POST['number2'];
if($_POST['group1'] == 'add') {
echo $number1 + $number2 = $answer;
}
else if($_POST['group1'] == 'subtract') {
echo $number1 - $number2 = $answer;
}
else if($_POST['group1'] == 'times') {
echo $number1 * $num2ber = $answer;
}
else if($_POST['group1'] == 'divide') {
echo $number2 / $number2 = $answer;
echo "<p>" . $answer . " </p>";
}
}
?>
<form name="number1" action="activity-2-4.php" method="post">
number1:<select name="number1">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select><br>
number2:<select name="number2">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select><br>
<input type="radio" name="group1" id="add" value="add">+<br/>
<input type="radio" name="group1" id="subtract" value="subtract">-<br/>
<input type="radio" name="group1" id="times" value="times">x<br/>
<input type="radio" name="group1" id="divide" value="divide">/<br/>
<button type="submit" name="subBtn" id="answerswer" value="answerswer">Calculate</button>
</form>
不要在echo语句中为变量赋值。此外,值被分配给的变量应该始终在左边。此外,你的回声在分水岭的最后一个eif内。
试试这个:
<?php
if (isset($_POST['subBtn']) && isset($_POST['group1'])) {
$number1 = isset($_POST['number1']) ? $_POST['number1'] : 0;
$number2 = isset($_POST['number2']) ? $_POST['number2'] : 0;
switch ($_POST['group1']) {
case 'add':
$answer = $number1 + $number2;
break;
case 'subtract':
$answer = $number1 - $number2;
break;
case 'times':
$answer = $number1 * $number2;
break;
case 'divide':
$answer = $number2 / $number2;
break;
default:
$answer = 'No operation method selected.';
break;
}
echo "<p>" . $answer . " </p>";
}
?>
我认为这是您的问题:
echo $number2 / $number2 = $answer
更改为:
$answer = $number2 / $number2
每个数学运算都是一样的。
您试图在存储数据的同时显示某些内容,但顺序错误。
在数学部分之后,你已经有了答案的回声。
您需要检查POST变量是否存在。
你使用错误的计算、变量和回声echo $number1 + $number2 = $answer;
我猜你的预期输出4+1=5
是这种格式。
<?php
if (isset($_POST['subBtn']))
{
$number1 = isset($_POST['number1']) ? $_POST['number1'] : '';
$number2 = isset($_POST['number2']) ? $_POST['number2'] : '';
$group1 = isset($_POST['group1']) ? $_POST['group1'] : '';
$answer = '';
$stmt = '';
switch ($group1)
{
case 'add':
$stmt = $number1.'+'.$number2.'= ';
$answer = $number1 + $number2;
break;
case 'subtract':
$stmt = $number1.'-'.$number2.'= ';
$answer = $number1 - $number2;
break;
case 'times':
$stmt = $number1.'*'.$number2.'= ';
$answer = $number1 * $number2;
break;
case 'divide':
$stmt = $number1.'/'.$number2.'= ';
$answer = $number1 / $number2;
break;
}
echo "<p>" . $stmt.$answer . " </p>";
}
?>
<form name="number1" action="activity-2-4.php" method="post">
number1:<select name="number1">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select><br>
number2:<select name="number2">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
<option value="6">6</option>
<option value="7">7</option>
<option value="8">8</option>
<option value="9">9</option>
<option value="10">10</option>
</select><br>
<input type="radio" name="group1" id="add" value="add">+<br/>
<input type="radio" name="group1" id="subtract" value="subtract">-<br/>
<input type="radio" name="group1" id="times" value="times">x<br/>
<input type="radio" name="group1" id="divide" value="divide">/<br/>
<button type="submit" name="subBtn" id="answerswer" value="answerswer">Calculate</button>
</form>
$number1 = (float)$_POST['number1'];
$number2 = (float)$_POST['number2'];
如果你知道你得到了一个int,你可以做
$number1 = (int)$_POST['number1'];
$number2 = (int)$_POST['number2'];
然而,我认为你的问题出在第1组。
print_r($_POST);
请确保其中有group1,并确保其小写值完全相同,因为您签入的是小写,并且此操作区分大小写。
然后下一步将是在屏幕上打印一些东西,并确保你在是否开始
echo "i'm in the add case";
依此类推
更改赋值方式。更改
$number1 + $number2 = $answer;
至
$answer = $number1 + $number2;