Google 应用脚本函数不返回表单响应

在谷歌应用程序脚本中，我编写以下代码来读取谷歌表单的响应

function formResponse() 
{
    var form = FormApp.openById('form-id');
    var formResponses = form.getResponses();
    for (var i = 0; i < formResponses.length; i++)
    {
      var formResponse = formResponses[i];
      var itemResponses = formResponse.getItemResponses();
      for (var j = 0; j < itemResponses.length; j++) 
      {
        var itemResponse = itemResponses[j];
        Logger.log('Response #%s to the question "%s" was "%s"',
        (i + 1).toString(),
        itemResponse.getItem().getTitle(),
        itemResponse.getResponse());
      }
    }
  return formResponses;
 }

在谷歌应用程序脚本日志已成功输入我所期望的内容。

在PHP中，我使用以下代码调用Google应用程序脚本。

$accessToken = $client->authenticate($request->input('code'));
$client->setAccessToken($accessToken);
$service = new 'Google_Service_Script($client);
$scriptId = 'MIQpTICu_Gobs7BEB-v3lHZZMYprHmXMAQrb';
// Create an execution request object.
$request = new 'Google_Service_Script_ExecutionRequest();
$request->setFunction('formResponse');
$responses = $service->scripts->run($scriptId, $request); 
$resp = $responses->getResponse();
print_r($resp);

它不会获得任何表单响应值