我数据库中的时间戳是2015-03-03 00:25:39（请注意，type = timestamp和我端正确的当前时间戳是2015-03-02 01:31:00。差异应该在23小时左右。但现在的问题是，网络中提供的答案会给我30小时，而不是23小时。我尝试过的一些代码如下：
$target是目标日期
CODE 1:
$then = strtotime($target);
$diff = $then - time();
echo sprintf("%s days and %s hours left", date('z', $diff), date('G', $diff));
但它给了我1天6小时的时间。所以30 hours
CODE2:
$seconds = strtotime("$target") - time();
echo $seconds; exit();
$days = floor($seconds / 86400);
$seconds %= 86400;
$hours = floor($seconds / 3600);
echo $hours;
它给了我类似107388=30小时的时间。
CODE 3:
//Convert to date
$datestr= $target;//Your date
$date=strtotime($datestr);//Converted to a PHP date (a second count)
//Calculate difference
$diff=$date-time();//time returns current time in seconds
$days=floor($diff/(60*60*24));//seconds/minute*minutes/hour*hours/day)
$hours=round(($diff-$days*60*60*24)/(60*60));
它给了我6个小时的
我不知道自己做错了什么，更像是不知道该怎么做。这是我的最后手段，因为我找不到对我有帮助的解决方案。期待您的快速回复。
PHP的DateTime()（和DateInterval()）在日期数学方面要好得多，并返回正确的结果：
$date = new DateTime('2015-03-03 00:25:39');
$now = new DateTime('2015-03-02 01:31:00');
$diff = $date->diff($now);
echo $diff->h, ' hours ', $diff->i, ' minutes';
演示
这是一个很晚的答案，但你的问题很好，将来可能会被搜索到。
这是一个在线演示。
// this doesn't appreciate any timezone declarations, you'll need to add this if necessary
$target="2015-03-03 00:25:39"; // declare your input
$then=new DateTime($target); // feed input to DateTime
$now=new DateTime(); // get DateTime for Now
$diff=(array)$then->diff($now); // calculate difference & cast as array
$labels=array("y"=>"year","m"=>"month","d"=>"day","h"=>"hour","i"=>"minute","s"=>"second");
$readable=""; // declare as empty string
// filter the $diff array to only include the desired elements and loop
foreach(array_intersect_key($diff,$labels) as $k=>$v){
if($v>0){ // only add non-zero values to $readable
$readable.=($readable!=""?", ":"")."$v {$labels[$k]}".($v>1?"s":"");
// use comma-space as glue | show value | show unit | pluralize when necessary
}
}
echo "$readable";
// e.g. 2 years, 20 days, 1 hour, 10 minutes, 40 seconds