/* 在$selected m 中,从 Java 代码中获取数据,这些数据成功地存储在 $selected 中。在查询中使用$selected,但在触发查询后无法获取任何数据。*/
$selected = $_GET['selected'];
$projects=mysql_query("select ProjectName from projects where LobID =
( select LobID from lob where LobName like ".$selected.");");
if (!$projects) {
echo "Could not successfully run query ($projects) from DB: " .mysql_error();
exit;
}
/* Have included this query in my php page. All the table names are same.Lob and projects are two different tables n LobID is primary key in Lob & Foreign key in projects. By executing the above query I am not able to fetch the data in $projects.Instead i am getting mesagecould not successfully run query. please help. */
查询应该是这样的
$projects=mysql_query("select ProjectName from projects where LobID =
(select LobID from lob where LobName like '$selected')");
将".$selected.");
更改为'$selected'
我认为应该是Jocker和Abdulla Nilam的答案的混合:
$projects=mysql_query("select ProjectName from projects
where LobID = ( select LobID from lob
where LobName like '%".$selected."%');");
或加入
$projects = mysql_query("SELECT ProjectName FROM projects
JOIN lob ON projects.LobID=lob.LobID
WHERE LobName LIKE '%" . $selected . "%');");
试试这个...如果您使用喜欢搜索 LobName 表示使用 %% 。它的重新运行可能匹配值 kike 单个字符
"select ProjectName from projects where LobID =
( select LobID from lob where LobName like '%$selected%');"
- 您的
$selected = $_GET['selected'];
变量中包含什么类型的数据? - 子查询返回多少行记录?
如果子查询返回更多记录,则可以限制结果数:
<?php
/**
...
**/
$selected = $_GET['selected'];
$projects = mysql_query("SELECT ProjectName FROM projects WHERE (LobID = (
SELECT LobID FROM lob WHERE LobName LIKE '%$selected%' LIMIT 1))");
?>
如果没有,您可以这样做:
<?php
/**
...
**/
$selected = $_GET['selected'];
$projects = mysql_query("SELECT ProjectName FROM projects WHERE (LobID IN (
SELECT LobID FROM lob WHERE LobName LIKE '%$selected%'))");
?>