这是原始数据
Array
(
[name] => me
[tickets] => Array
(
[1] => Array
(
[equipment] => Array
(
[1] => Array
(
[name] => DVR
[received] => 10
)
[2] => Array
(
[name] => DCT
[received] => 3
)
)
)
[2] => Array
(
[equipment] => Array
(
[1] => Array
(
[name] => DVR
[received] => 4
)
[2] => Array
(
[name] => DCT
[received] => 6
)
)
)
)
)
用户有多个工单，但每个工单都有相同的项目，但"收到"的金额不同。我想将收到的金额sum到一个变量/数组中。
这是我希望如何让它像
Array
(
[name] => me
[equipment] => Array
(
[DVR] => 14
[DCT] => 9
)
)
这是我最近一次尝试从多维数组构建自己的数组的失败尝试。
foreach($data as $user){
$sum = [];
$sum['name'] = $user->name;
$sum['equipment'] = [];
foreach($user->tickets as $ticket){
foreach($ticket->equipments as $eqpt){
$sum['equipment'][$eqpt['name']] += $eqpt['pivot']['received'];
}
}
print_r($sum);
}
请尝试以下代码。但是，您的$data中只有一个用户，因此您需要先执行$data = [$data];。
foreach ($data as $user) {
$sum = [];
$sum['name'] = $user['name'];
$sum['equipment'] = [];
foreach($user['tickets'] as $ticket){
foreach($ticket['equipment'] as $eqpt){
$sum['equipment'][$eqpt['name']] += $eqpt['received'];
}
}
print_r($sum);
}
- PHP 数组使用方括号语法访问
$ticket->equipments可能有错别字.
试试这个：
$array = $data; //$data is your array
$sum = array('name' => $array['name'], 'equipment' => array());
foreach($array['tickets'] as $row) {
for($i = 0; $i < count($row); $i++) {
foreach($row['equipment'] as $infos) {
$sum['equipment'][$infos['name']] += $infos['received'];
//print_r($infos);
}
}
}
print_r($sum);
好吧，经过大量的谷歌搜索和反复试验，这似乎有效
$sum = [];
// $data is a collection returned by Laravel
// I am converting it to an array
foreach($data->toArray() as $user){
$items = [];
foreach($user['tickets'] as $ticket){
foreach($ticket['equipments'] as $eqpt){
$name = $eqpt['name'];
if (! isset($items[$name]))
{
$items[$name] = $eqpt['received'];
} else {
$items[$name] += $eqpt['received'];
}
}
}
$sum[] = [
'name' => $user['name'],
'equipment' => $items
];
}
@tsnorri @Adrian 西德·阿尔马格尔