我有table_1和table_2，它们是相同的结构，但数据不同。需要以某种create_date的方式从该表中获取所有数据，无论来自哪个表（它可以是 table_1 的 1 行，table_2 的 3 行，然后是 table_1 的 3 行）。可能吗？如何？或者大喊我得到两个查询，然后用 PHP 按日期排序？
编辑：对不起，第一部分，我以为我可以从那里做到，但似乎我不能：/
我有这样的大查询
SELECT
table_1.id,
table_1.created,
table_1.qty,
table_1.comments,
table_1.last_update,
table_7.firstname,
SUBSTRING(table_7.lastname, 1, 1) AS lastname,
table_8.title country,
table_3.value AS sim,
table_1.offer_request,
table_5.manufacturer AS manufacturer,
table_4.name AS model,
table_6.value AS specifications,
table_9.value as shipping,
table_1.model AS mid,
table_1.user_id,
table_1.callme,
table_1.phoneprice,
table_1.phoneprice_eur,
table_1.currency,
table_1.sel_buy_show_all,
table_1.seller_buyer
FROM (`table_1`)
LEFT JOIN `table_3` ON `table_3`.`id` = `table_1`.`sim`
LEFT JOIN `table_4` ON `table_4`.`id` = `table_1`.`model`
LEFT JOIN `table_5` ON `table_5`.`id` = `table_1`.`manufacturer`
LEFT JOIN `table_6` ON `table_6`.`id` = `table_1`.`specifications`
LEFT JOIN `table_7` ON `table_7`.`id` = `table_1`.`user_id`
LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id`
LEFT JOIN `table_9` ON `table_9`.`id` = `table_1`.`types`
WHERE `table_1`.`status` = '1'
AND `table_1`.`deleted` = '0'
ORDER BY `last_update` DESC
LIMIT 200
并且table_1哪种结构与table_2相同，我需要以某种方式将table_2插入到具有所有连接的查询中，例如table_1
如果我
答对了你的问题，你可以像这样使用联合 -
select * from table_1 union select * from table_2 order by create_date desc
编辑
创建这样的视图 -
create view table_1And2 as select * from table_1 union select * from table_2
table_1And2不是一个好名字，就给一个有意义的名字。
并像这样修改您的长查询 -
SELECT
table_1And2.id,
table_1And2.created,
table_1And2.qty,
table_1And2.comments,
table_1And2.last_update,
table_7.firstname,
SUBSTRING(table_7.lastname, 1, 1) AS lastname,
table_8.title country,
table_3.value AS sim,
table_1And2.offer_request,
table_5.manufacturer AS manufacturer,
table_4.name AS model,
table_6.value AS specifications,
table_9.value as shipping,
table_1And2.model AS mid,
table_1And2.user_id,
table_1And2.callme,
table_1And2.phoneprice,
table_1And2.phoneprice_eur,
table_1And2.currency,
table_1And2.sel_buy_show_all,
table_1And2.seller_buyer
FROM (`table_1And2`)
LEFT JOIN `table_3` ON `table_3`.`id` = `table_1And2`.`sim`
LEFT JOIN `table_4` ON `table_4`.`id` = `table_1And2`.`model`
LEFT JOIN `table_5` ON `table_5`.`id` = `table_1And2`.`manufacturer`
LEFT JOIN `table_6` ON `table_6`.`id` = `table_1And2`.`specifications`
LEFT JOIN `table_7` ON `table_7`.`id` = `table_1And2`.`user_id`
LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id`
LEFT JOIN `table_9` ON `table_9`.`id` = `table_1And2`.`types`
WHERE `table_1And2`.`status` = '1'
AND `table_1And2`.`deleted` = '0'
ORDER BY `last_update` DESC
LIMIT 200
我也看到@Rehban的答案对你来说是一个很好的答案，如果你不需要view，我会提出另一个解决方案：
SELECT
mainTable.id,
mainTable.created,
mainTable.qty,
mainTable.comments,
mainTable.last_update,
table_7.firstname,
SUBSTRING(table_7.lastname, 1, 1) AS lastname,
table_8.title country,
table_3.value AS sim,
mainTable.offer_request,
table_5.manufacturer AS manufacturer,
table_4.name AS model,
table_6.value AS specifications,
table_9.value as shipping,
mainTable.model AS mid,
mainTable.user_id,
mainTable.callme,
mainTable.phoneprice,
mainTable.phoneprice_eur,
mainTable.currency,
mainTable.sel_buy_show_all,
mainTable.seller_buyer
FROM (Select * From `table_1` union Select * From `table_2`) as mainTable
LEFT JOIN `table_3` ON `table_3`.`id` = `mainTable `.`sim`
LEFT JOIN `table_4` ON `table_4`.`id` = `mainTable `.`model`
LEFT JOIN `table_5` ON `table_5`.`id` = `mainTable `.`manufacturer`
LEFT JOIN `table_6` ON `table_6`.`id` = `mainTable `.`specifications`
LEFT JOIN `table_7` ON `table_7`.`id` = `mainTable `.`user_id`
LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id`
LEFT JOIN `table_9` ON `table_9`.`id` = `mainTable `.`types`
WHERE `mainTable `.`status` = '1'
AND `mainTable `.`deleted` = '0'
ORDER BY `last_update` DESC
LIMIT 200