php.net 文档中有一个非常好的函数,它使您能够以Facebook风格的方式格式化时间(例如,2 minutes ago
,4 weeks ago
或3 years ago
)。
但是,我更喜欢Stackoverflow和Apple Mail的方式,通常如下:
- 当前日期以
x seconds ago
、x hours ago
或时间(例如4:35pm
)列出。
昨天 - 被列为"昨天"。
- 之后的所有日子都按 M/D/Y 列出。
有没有人改编这个 php.net 脚本来做到这一点,或者可能共享一个不同的脚本来实现相同的目标?
<?php
function nicetime($date)
{
if(empty($date)) {
return "No date provided";
}
$periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
$lengths = array("60","60","24","7","4.35","12","10");
$now = time();
$unix_date = strtotime($date);
// check validity of date
if(empty($unix_date)) {
return "Bad date";
}
// is it future date or past date
if($now > $unix_date) {
$difference = $now - $unix_date;
$tense = "ago";
} else {
$difference = $unix_date - $now;
$tense = "from now";
}
for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
$difference /= $lengths[$j];
}
$difference = round($difference);
if($difference != 1) {
$periods[$j].= "s";
}
return "$difference $periods[$j] {$tense}";
}
$date = "2009-03-04 17:45";
$result = nicetime($date); // 2 days ago
?>
好的,我回答了我自己的问题。
关键是跟踪for
循环经历了多少轮除法,直到当前时间的商减去输入时间 $difference
$j
$lengths
数组项的第 个值小于该数组的第 $j+1
个值。
我通过增加变量$i
来跟踪这一点(请注意if/elseif/else
子句演示了我上面提到的 3 点中的每一点)在这个修改后的 nicetime()
中:
///http://php.net/manual/en/function.time.php
function nicetime($date)
{
if(empty($date)) {
return "No date provided";
}
$periods = array("second", "minute", "hour", "day", "week", "month", "year", "decade");
$lengths = array("60","60","24","7","4.35","12","10");
$now = time();
$unix_date = strtotime($date);
// check validity of date
if(empty($unix_date)) {
return "Bad date";
}
// is it future date or past date
if($now > $unix_date) {
$difference = $now - $unix_date;
$tense = "ago";
} else {
$difference = $unix_date - $now;
$tense = "from now";
}
$i=0;
for($j = 0; $difference >= $lengths[$j] && $j < count($lengths)-1; $j++) {
$i++;
$difference /= $lengths[$j];
}
$difference = round($difference);
if($difference != 1) {
$periods[$j].= "s";
}
if($i<3){
$day="$difference $periods[$j] {$tense}";
return $day;
//satisfies case #1 where time is listed as seconds, minutes, hours ago
}
elseif($i==3){
$difference == 1 && $periods[$j]=='day' ? $day='yesterday':
$day="$difference $periods[$j] {$tense}";
return $day;
//satisfies case #2 where time is listed as yesterday if not the current day
}
else{
return $date;
// satisfies case #3 where date is listed as M/D/Y if greater than a week old
}
}
echo "case#1: ".nicetime('2012-08-13 23:12:16');
echo "case#2: ".nicetime('2012-08-12 23:12:16');
echo "case#3: ".nicetime('2012-07-07 23:12:16');