>我在 php 中有一个字符串作为
$str = "@113_Miscellaneous_0 = 0@,@104_documentFunction_0 = 1@";
如何应用正则表达式，以便我可以提取@字符之间的字符串这样结果的结果将是一个数组，比如
result[0] = "113_Miscellaneous_0 = 0";
result[1] = "104_Miscellaneous_0 = 1";
@Fluffeh 感谢您的编辑@乌特卡诺斯 - 尝试过这样的事情
$ptn = "@(.*)@";
preg_match($ptn, $str, $matches);
print_r($matches);
output:
Array
(
[0] => '"113_Miscellaneous_0 = 0'",'"104_documentFunction_0 = 1'"
[1] => '"113_Miscellaneous_0 = 0'",'"104_documentFunction_0 = 1'"
)
使用非贪婪匹配，
preg_match_all("/@(.*?)@/", $str, $matches);
var_dump($matches);
你可以以不同的方式去做：
$str = str_replace("@", "", $str);
$result = explode(",", $str);
编辑
好吧，试一试：
$ptn = "/@(,@)?/";
$str = "@113_Miscellaneous_0 = 0@,@104_documentFunction_0 = 1@";
preg_split($ptn, $str, -1, PREG_SPLIT_NO_EMPTY);
结果：
Array
(
[0] => 113_Miscellaneous_0 = 0
[1] => 104_documentFunction_0 = 1
)