如何使用 PHP 根据表达式替换段落中的字符串 - How to replace the string in a paragraph based on expression using PHP

How to replace the string in a paragraph based on expression using PHP

这里有一个示例段落$input_str

$input_str = 'Some text is here......[$radio_yes: He is eligible for PF. / $radio_no: He is not eligible for PF.]....Some text is here';
$control_name = 'radio_yes';

根据$control_name替换段落内容$input_str。

 if($control_name=='radio_yes') Then
    {
        I want to the result : $result_str = 'Some text is here......He is eligible for PF......Some text is here';
    }
    else if($control_name=='radio_no') Then
    {
        I want to the result :  $result_str = 'Some text is here......He is not eligible for PF.....Some text is here';
    }

真的我不知道PHP字符串函数。如何使用字符串函数或其他方式。谢谢大家。

$string = preg_match('~/(.*?)]~', $input_str, $output);

我的解决方案是将$input_str分成 3 个部分，之前、控制器和之后。~~然后我们使用基于$control_name的开关，~~最后我们匹配与该controller关联的文本并将各个部分放在一起，即：

<?php
$input_str = 'Some text is here......[$radio_yes: He is eligible for PF. / $radio_no: He is not eligible for PF.]....Some text is here';
$control_name = 'radio_yes';
preg_match_all('/^(.*?)'[(.*?)'](.*?)$/si', $input_str, $matches, PREG_PATTERN_ORDER);
$before = $matches[1][0];
$controllerRaw = $matches[2][0];
$after = $matches[3][0];
preg_match_all("/$control_name:(.*?)'./si", $controllerRaw, $controller, PREG_PATTERN_ORDER);
$controller = $controller[1][0];
echo "$before $controller $after";

只要模式相同，上面的代码应该适用于任何$input_str，some text... [ controller: some text ending with. ] more text...

IdeoneDemo

//Your input text;
$input_string = 'Some text is here......[$radio_yes: He is eligible for PF. / $radio_no: He is not eligible for PF.]....Some text is here';
//The text inside the input text you want to be replaced:
$pattern = '/['$radio_yes: He is eligible for PF. / '$radio_no: He is not eligible for PF.]/'
//conditional that decides what the $pattern will be replaced with:
if($control_name=='radio_yes')
{
  $replaceWith = 'He is eligible for PF';
}
else($control_name=='radio_no')
{
  $replaceWith = 'He is not eligible for PF';
}
//replacing the $pattern and giving the result to $newString
$newString = preg_replace($pattern, $replaceWith, $input_string);
echo $newString;//printing out the results

让我知道这是否适合您。

这样的正则表达式从字符串中获取无线电的名称和值。preg_replace_callback可以通过control_name值来更改它。如果control_name不等于任何找到的值，则返回空字符串

echo preg_replace_callback('~'['$('w+):(.+)/'s*'$('w+):(.+)']~', 
     function($m) use ($control_name) {
       if ($control_name == $m[1]) 
          return $m[2];
       if ($control_name == $m[3]) 
          return $m[4];
       return "";
     },
     $input_str);

演示