>我需要去掉 JSON 字符串中的双引号，这就是我形成数组然后将其转换为 JSON 的方式
$dinnerDetails = array();
foreach ($dinners as $dinner) {
$dinnerDetails[] = array(
"title" => $dinner->getName(),
"data" => $dinner->getDate()
);
}
$dinnerDetails = json_encode($dinnerDetails);
当我转储$dinnerDetails时，在我的视图中，我看到以下内容
string '[
{
"title": "Formal Dinner",
"data": "Tue Apr 05 2016 05:00:00 GMT+0500 (PKT)"
},
{
"title": "Formal Dinner",
"data": "Tue Apr 05 2016 05:00:00 GMT+0500 (PKT)"
},
{
"title": "Black Tie",
"data": "Wed Apr 13 2016 05:00:00 GMT+0500 (PKT)"
},
{
"title": "Formal Dinner",
"data": "Fri Apr 08 2016 05:00:00 GMT+0500 (PKT)"
}
]
当我将其分配给JS变量时，这就是在源代码中看到它的方式
var dinners = [
{
"title": "Formal Dinner",
"data": "Tue Apr 05 2016 05:00:00 GMT+0500 (PKT)"
},
{
"title": "Formal Dinner",
"data": "Tue Apr 05 2016 05:00:00 GMT+0500 (PKT)"
},
{
"title": "Black Tie",
"data": "Wed Apr 13 2016 05:00:00 GMT+0500 (PKT)"
},
{
"title": "Formal Dinner",
"data": "Fri Apr 08 2016 05:00:00 GMT+0500 (PKT)"
},
{
"title": "Formal Dinner",
"data": "Sat Apr 16 2016 05:00:00 GMT+0500 (PKT)"
},
{
"title": "Formal Dinner",
"data": "Mon Mar 28 2016 05:00:00 GMT+0500 (PKT)"
}
];
我正在使用Symfony框架，这就是我传递$dinnerDetails查看的方式
return $this->render('AppBundle:admin/college:edit.html.twig', array(
'dinners' => $dinnerDetails
));
然后在树枝内部，我像这样分配给 js 变量
var dinner = jQuery.parseJSON(dinners);
在JS中，我什至尝试做JSON.parse(dinners.replace(""",'"'));但这无济于事。
我正在寻找的输出是这样的
[
{
title: "All Day Event",
date: "Fri Apr 08 2016 05:00:00 GMT+0500",
},
{
title: "Long Event",
date: "Fri Apr 08 2016 05:00:00 GMT+0500",
},
]
我将非常感谢这里的帮助。
尝试模板中的原始过滤器。像这样：
{{ dinners|raw }}
2nd. 您已将 PHP 对象序列化为 JSON 字符串。
如果将此字符串粘贴到脚本块中，则此字符串将被解释为 JS。
它现在是JS代码，不再是字符串。您不必解析它;实际上您无法解析它。
<script> var dinner = {{ dinners|raw }}; </script>
在你的控制器或php文件中使用以下代码。
<?php
$arrDinnerDetails = array();
foreach ($dinners as $dinner)
{
$arrDinnerDetails[] = array(
"title" => $dinner->getName(),
"data" => $dinner->getDate()
);
}
return $this->render('AppBundle:admin/college:edit.html.twig', array(
'arrDinnerDetails' => $arrDinnerDetails
));
?>
在视图文件中，使用以下代码。
<script>
var strJsonDinner = JSON.stringify('<?php echo json_encode($arrDinnerDetails); ?>');
</script>