我想删除PHP中这个短语后面的字符串中的所有内容:
On 17 Mar 2015
我将如何匹配任何日期?
编辑:我目前使用这个来删除字符串中的短语及其后的所有内容:
if (strpos($body,"On 17 Mar 2015") !== false) { $body = substr($body, 0, strpos($body, "On 17 Mar 2015"));}
输入=
reply reply reply reply reply reply reply reply
On 17 Mar 2015, at 10:23, user wrote:
> email email email email email email email email email email email email
> email email email email email email email email email email email email
预期输出:
reply reply reply reply reply reply reply reply
对于任何可能的日期
如果短语的格式没有改变,下面的正则表达式应该可以对任何可能的日期起作用。
$phrase = "On 17 Mar 2015";
preg_match("#(?<=On's)'d+'s'w+'s'd+#", $phrase, $matches);
echo $matches[0];