我正在尝试从数据库中的数据中获取数据，并执行json_encode
$data = json_encode($results);
当我放入echo（$data）；die（）；我得到了以下结果
[{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"Wa","PRODUCT_GROUP":"ACP'S","NET_SALES":"187002.04","RANK":"1"},{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"CVS","PRODUCT_GROUP":"ACP'S","NET_SALES":"127948.68","RANK":"2"},{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"McK","PRODUCT_GROUP":"ACP'S","NET_SALES":"81079.29","RANK":"3"},{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"Car","PRODUCT_GROUP":"ACP'S","NET_SALES":"65320.42","RANK":"4"},{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"Krog.","PRODUCT_GROUP":"ACP'S","NET_SALES":"31977.95","RANK":"5"}]
在jquery代码中，我试图解析JSON$数据，如下所示
$(function () {
var data = new Array();
data = $.parseJSON('<?php echo $data; ?>'); //error occuring here
//other code goes here
});
我在data = $.parseJSON('<?php echo $data; ?>'); 附近收到一个错误Uncaught SyntaxError: Unexpected identifier
我在中得到以下输出
[{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"Wa","PRODUCT_GROUP":"ACP'S","NET_SALES":"187002.04","RANK":"1"},{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"CVS,Inc.","PRODUCT_GROUP'S":"ACP","NET_SALES":"127948.68","RANK":"2"},{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"McK","PRODUCT_GROUP":"ACP'S","NET_SALES":"81079.29","RANK":"3"},{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"Car","PRODUCT_GROUP":"ACP'S","NET_SALES":"65320.42","RANK":"4"},{"CAL_DATE":"01-JUN-13","CUSTOMER_TEXT":"Krog.","PRODUCT_GROUP":"ACP'S","NET_SALES":"31977.95","RANK":"5"}]
有谁能告诉我为什么我在那行出错吗？提前感谢
这是一个有效的json，所以您不需要解析它：
data = <?php echo $data; ?>
我想你想这样使用它：
$(function () {
var data = '<?php echo $data; ?>';
data = $.parseJSON(data); //error occuring here
//other code goes here
});
来自文件：
获取格式良好的JSON字符串，返回结果JavaScript值。
从文档中检查：
var obj = jQuery.parseJSON( '{ "name": "John" }' ); // results in {"name" : "John"}
alert( obj.name === "John" );
'{ "name": "John" }'是一个json格式的字符串。