我正在FB上收集数据并将其发送到我的DB。我的应用程序正在运行，我可以看到数据插入到我的数据库中，但我遇到了一个错误，我不知道如何解决。我对此进行了研究，并尝试了一些没有结果的解决方案。我添加了一行代码来查看错误是什么。请指导我解决它。谢谢
错误：
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource
Unknown column 'id' in 'where clause'
错误指向这一行：
$result = mysql_fetch_array($query) or die ( mysql_error () );
这是我的代码：
<?php
define('db_user','xxx');
define('db_password','xxx');
define('db_host','xxx.xxx.com');
define('db_name','xxx');
// Connect to MySQL
$dbc = @mysql_connect (db_host, db_user, db_password) OR die ('Could not connect to MySQL: ' . mysql_error() );
// Select the correct database
mysql_select_db (db_name) OR die ('Could not select the database: ' . mysql_error() );
mysql_set_charset('utf8',$dbc);
require 'src/facebook.php';
// Create our Application instance (replace this with your appId and secret).
$facebook = new Facebook(array(
'appId' => 'xxxx',
'secret' => 'xxxx',
'cookie' => true));
// Get User ID
$user = $facebook->getUser();
// We may or may not have this data based on whether the user is logged in.
//
// If we have a $user id here, it means we know the user is logged into
// Facebook, but we don't know if the access token is valid. An access
// token is invalid if the user logged out of Facebook.
if ($user) {
try {
// Proceed knowing you have a logged in user who's authenticated.
$fbuid = $facebook->getUser();
$user_profile = $facebook->api('/me');
} catch (FacebookApiException $e) {
error_log($e);
$user = null;
}
}else{
header('Location: index.php');
}
$query = mysql_query("SELECT * FROM users WHERE oauth_provider = 'facebook' AND oauth_uid = ". $user_profile['id']);
$result = mysql_fetch_array($query);
if(empty($result)){
$query = mysql_query("INSERT INTO users (oauth_provider, oauth_uid, username, first_name, last_name, birthday, email, pic_square ) VALUES ('facebook', {$user_profile['id']}, '{$user_profile['name']}', '{$user_profile['first_name']}','{$user_profile['last_name']}','{$user_profile['birthday']}','{$user_profile['email']}', '{$user_profile['pic_square']}')");
$query = mysql_query("SELECT * FROM users WHERE id = " . mysql_insert_id());
$result = mysql_fetch_array($query) or die ( mysql_error () );
}
// Login or logout url will be needed depending on current user state.
if ($user) {
$paramsout = array('next'=>'http://www.mywebsite.com/test/logout.php');
$logoutUrl = $facebook->getLogoutUrl($paramsout);
}
?>
<html><body>welcome</body></html>
我相信失败的查询是这个：
$query = mysql_query("SELECT * FROM users WHERE id = " . mysql_insert_id());
正如错误消息所说，表users不包含名为id的字段。
检查数据库中的字段名称，更新查询，它应该可以工作。
"where子句"中的未知列"id"
你真的有一个名为id的列吗？检查以确保这确实是您为列命名的名称。
如果您没有名为id的列，可以使用以下方法添加：
ALTER TABLE `users` ADD `id` INT( 11 ) NOT NULL AUTO_INCREMENT FIRST
使用AUTO_INCREMENT，列"id"将自动为您插入数据库的每一行分配一个新的id编号，您在此处提供的代码将起作用。