将json响应格式化为父级和子级 - format json response into parent and child

format json response into parent and child

本文关键字：json 响应格式化 | 更新日期: 2023-09-27

嗨，我收到了一个查询的响应。回复如下：

{ data: [
       {
       parent: "summer",
       image: "template/assets/x354.jpg",
       productName: "United Colors of Benetton"    },   {   parent: "autumn",   image: "template/assets/x354.jpg",   productName: "United
   Colors of Benetton" }, { parent: "summer", image:
   "template/assets/x354.jpg", productName: "Puma Running Shoes" } ] }

基本上，我想要php中的一个函数来格式化这个响应。这个在这种情况下，响应中的同一父母是"夏天"，数据夏天的名字应该印在下面。也就是说，夏天应该是父母的数据。所需的响应是：

{ data: [
       {
        parent: "autumn",
        image: "template/assets/x354.jpg", productName: "United Colors of Benetton" }, { parent: "summer" [{ image:
   "template/assets/x354.jpg", productName: "United Colors of Benetton"
   }, { image: "template/assets/x354.jpg", productName: "Puma Running
   Shoes" } ] }
   ] }

您发布的查询响应似乎不是有效的JSON，因为对象属性不是带引号的字符串，您必须注意这一点，才能使用json_decode()解析JSON字符串。（请参见https://stackoverflow.com/a/6941739/846987例如。）

这应该会产生你想要的输出：

<?php
$json = <<<EOT
{
    "data": [
        {
            "parent": "summer",
            "image": "template'/assets'/x354.jpg",
            "productName": "United Colors of Benetton"
        },
        {
            "parent": "autumn",
            "image": "template'/assets'/x354.jpg",
            "productName": "United Colors of Benetton"
        },
        {
            "parent": "summer",
            "image": "template'/assets'/x354.jpg",
            "productName": "Puma Running Shoes"
        }
    ]
}
EOT;
$jsonObject = json_decode($json);
$categories = array();
foreach($jsonObject->data as $element) {
  if ( ! isset($categories[$element->parent])) {
    $categories[$element->parent] = array();
  }
  $categories[$element->parent][] = $element;
  unset($element->parent);
}
echo '<pre>' . json_encode($categories, JSON_PRETTY_PRINT) . '</pre>';